Answer:
5.62 m/s
Explanation:
Newton's law of motion can be used to determine the maximum speed of the elevator. In the question, we are given:
Force exerted by the elevator (R) = 1.7 times the weight of the passenger (m*g)
Thus: R = 1.7*m*g
Distance (s) = 2.3 m
Newton's second law of motion: R - m*g = m*a
1.7*m*g - m*g = m*a
a = 0.7*m*g/m = 0.7*g = 0.7*9.8 = 6.86 m/s²
To determine the maximum speed:
Therefore, the elevator maximum speed is equivalent to 5.62 m/s.
The momentum of block B afterwards is .
Explanation:
We can solve this problem by applying the principle of conservation of momentum.
In fact, the total momentum before and after the collision must be conserved. Therefore, we can write:
where:
is the initial momentum of block A
is the initial momentum of block B
is the final momentum of block A
is the final momentum of block B
Solving for , we find:
So, the momentum of block B afterwards is .
Learn more about momentum:
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