A) sodium fluoride
B) rubidium oxide
C) boron trichloride
D) dihydrogen selenide
E) tetraphosphate hexoxide
F) iodine trichloride
Answer:
V = 80.65L
Explanation:
Volume = ?
Number of moles n = 5 mol
Temperature (T) = 393.15K
Pressure = 1520mmHg
Ideal gas constant (R) = 62.363mmHg.L/mol.K
According to ideal gas law,
PV = nRT
P = pressure of the ideal gas
V = volume the gas occupies
n = number of moles of the gas
R = ideal gas constant (note this can varies depending on the unit of your variables)
T = temperature of the ideal gas
PV = nRT
Solve for V,
V = nRT / P
V = (5 * 62.363 * 393.15) / 1520
V = 80.65L
The volume the gas occupies is 80.65L
Answer:
0.404M
Explanation:
...<em>To make exactly 100.0mL of solution...</em>
Molar concentration is defined as the amount of moles of a solute (In this case, nitrate ion, NO₃⁻) in 1 L of solution.
To solve this question we need to convert the mass of Fe(NO₃)₃ to moles. As 1 mole of Fe(NO₃)₃ contains 3 moles of nitrate ion we can find moles of nitrate ion in 100.0mL of solution, and we can solve the amount of moles per liter:
<em>Moles Fe(NO₃)₃ -Molar mass: 241.86g/mol-:</em>
3.26g * (1mol / 241.86g) =
0.01348 moles Fe(NO₃)₃ * (3 moles of NO₃⁻ / 1mole Fe(NO₃)₃) =
<em>0.0404 moles of NO₃⁻</em>
In 100mL = 0.1L, the molar concentration is:
0.0404 moles of NO₃⁻ / 0.100L =
<h3>0.404M</h3>
Answer:
The pressure equilibrium constant (Kp) = (P O₂)³/(P CO₂)²(P H₂O)⁴.
Explanation:
<em>2CO₂ (g) + 4H₂O (g) → 2CH₃OH (l) + 3O₂ (g).</em>
<em></em>
The pressure equilibrium constant (Kp) = the product of the pressure of the products side components / the product of the pressure of the reactantss side components.
each one is raised to a power equal to its coefficient.
<em>∴ The pressure equilibrium constant (Kp) = (P O₂)³/(P CO₂)²(P H₂O)⁴.</em>
