Sulfur dioxide has a molecular formula of SO2. The balanced
chemical reaction leading to this isas shown below:
<span>S + O2 --->
SO2</span>
Therefore this means that 1 mole of sulfur and 1 mole of O2
reacts to form 1 mol of sulfur dioxide.
Assuming 1 mol of O2 and 1 mol of S for the sake of
calculation, therefore:
mass oxygen, O = (1 mol O2) (2 mol O/ 1 mol O2) (16 g O/
mol O) = 32 g O
mass sulfur, S = 1 mol (32 g / mol) = 32 g
Therefore the ratio of O to S is:
O:S = 32 g O / 32 g S = 1 g O2/ 1 g S
<span>Hence, there is 1 g of oxygen per 1 g of sulfur in sulfur
dioxide.</span>
True, The products obtained by the acid-catalyzed hydration of 1-methylcyclohexene and 1-methylenecyclohexane are identical.
Methylcyclohexane is a colorless liquid with a faint, Benzene-like smell. it's miles used as a solvent and to manufacture organic chemical substances.
The extra fantastically substituted alkene is 1-methylcyclohexene, given that there's only one H substituent at the double bonded carbons. that is the predominant product. whilst injected repeatedly. methylcyclohexane proved to be poisonous for the liver, heart, and kidney at a high dose. absolutely the toxic dose changed into. at the same time as the no discovered destructive effect stage. The substance exerted little impact on the reproductive system.
Methylcyclohexane, as a aspect of a mixture, is usually dehydrogenated to toluene, which will increase the octane rating of gas. It may be produced by means of a Wittig response or a reaction with a reagent from cyclohexanone. it can additionally be synthesized as a side made of the dehydration of 2-methylcyclohexanol into 1-methylcyclohexene.
Learn more about 1-methylcyclohexene here:-brainly.com/question/14855251
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Answer:
yes
Explanation:
the number of protons in the nucleus of an atom determines the type element: the number of protons in an element is the atomic number on the periodic table (number at the top)
S=50.05/32 O=49.95/16, S=1.5640625/1.5640625 O=3.121875/1.5640625, S=1 O=1.99, S=1 O=2 Empirical Formula= SO2
Answer:
55.18 L
Explanation:
First we convert 113.4 g of NO₂ into moles, using its molar mass:
- 113.4 g ÷ 46 g/mol = 2.465 mol
Then we<u> use the PV=nRT formula</u>, where:
- P = 1atm & T = 273K (This means STP)
- R = 0.082 atm·L·mol⁻¹·K⁻¹
Input the data:
- 1 atm * V = 2.465 mol * 0.082atm·L·mol⁻¹·K⁻¹ * 273 K
And <u>solve for V</u>: