1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dmitriy555 [2]
3 years ago
13

I have a sample of galena. It appears there may be some gold in it. It is a piece of raw ore so I took it to a metallurgist and

that's what he said. Is that possible?
Chemistry
1 answer:
Lubov Fominskaja [6]3 years ago
7 0

Yes it is possible

Explanation:

Galena and gold can become encrusted together. They can form together in the same geologic setting.

  • Gold usually occurs freely in nature uncombined with other atoms.
  • Galena is the largest ore of lead.
  • Both minerals can become twinned under appropriate geologic conditions.
  • They are usually seen in pegmatitic intrusions in a rock body as product of late stage melt crystallization.

learn more:

Renewable resources brainly.com/question/4344417

#learnwithBrainly

You might be interested in
Give an example of two elements that would form a covalent bond
Tamiku [17]

<span>Hydrogen carbon and oxygen commonly form covalent bonds.
</span>
HOPE THIS HELPS!
4 0
3 years ago
Since both HBr and KOH are strong, we expect these reactions to occur fully. You mix 2 moles of HBr with 3 moles of KOH in enoug
AysviL [449]

Answer: pH = 14

Explanation: Please see the attachments below

8 0
3 years ago
How many significant figures are in this number?<br> 9.678 grams
KengaRu [80]
There are 4 of them
5 0
3 years ago
Read 2 more answers
Solve
stiv31 [10]

The volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.

<h3>How to calculate volume?</h3>

The volume of a given gas can be calculated using the following Charle's law equation:

V1/T1 = V2/T2

Where;

  • T1 = initial temperature
  • T2 = final temperature
  • V1 = initial volume
  • V2 = final volume

  • V1 = 9L
  • V2 = ?
  • T1 = 325K
  • T2 = 450K

9/325 = V2/450

325V2 = 4050

V2 = 4050/325

V2 = 12.46L

Therefore, the volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.

Learn more about volume at: brainly.com/question/2817451

7 0
2 years ago
Determine whether the variable is qualitative or quantitative. grams of carbohydrates in a donut. grams of carbohydrates in a do
Sophie [7]
You would know that the variable is quantitative if it shows any number to express the quantity. For example, quantitative variables are 50°C, 5 atm, 2 moles, 100 L and so on. A variable is qualitative if it expresses a relative quantity but not expressing a number. Examples would be: few, too hot, several, or even describing the characteristics of a variable. Hence, when the variable is in grams, then that would be quantitative.
4 0
3 years ago
Other questions:
  • Contrast solid nonmetals and solid metals.
    8·1 answer
  • Why does the structure of the plasma membrane make this type of transport necessary for fluids
    9·1 answer
  • Rust is formed by the interaction of iron and oxygen. When rust formed on an iron nail with a mass of 100 g, the mass of the rus
    8·1 answer
  • What is NADPH2 ? where is it used?
    13·1 answer
  • An acid-base titration is a neutralization reaction performed to determine: the concentration of an unknown acid based upon the
    11·1 answer
  • One container is filled with argon gas and the other with krypton gas. If both gases have the same temperature, in which contain
    12·1 answer
  • Question 1 (True/False Worth 4 points) (03.06 LC) An instantaneous dipole occurs when a molecule's moving electrons are briefly
    10·2 answers
  • Franklin used X-ray crystallography to determine that the shape of the dna molecule is what
    15·1 answer
  • Which structures join with the cell’s membrane during exocytosis?
    10·1 answer
  • Which refers to the bending of a wave as it passes through one medium to another medium?
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!