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Umnica [9.8K]
4 years ago
14

When 7.0 mol Al react with 8.5 mol HCl, what is the limiting reactant and how many moles of AlCl3 can be formed?

Chemistry
2 answers:
Tcecarenko [31]4 years ago
4 0
Option 2 is Correct.
because, in the standard reaction, 2 moles of Al reacts with 6 of moles of HCl.
if 7 moles of Al are there, it will require 21 mole of HCl. So HCl Is the limiting reagent.

Now, 6 moles of HCl gives 2 moles of AlCl3, then 8.5 moles of HCl will give 2.84 moles of AlCl3.

crimeas [40]4 years ago
4 0

B. HCl is the limiting reactant; 2.8 mol AlCl3 can be formed

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Explanation:

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In this case, since we are given the volume of N2O3 and pressure and temperature for the STP (1.00 atm and 273.15 K), we can compute the moles, considering the ideal gas equation as shown below:

PV=nRT\\\\n=\frac{PV}{RT} \\\\n=\frac{1atm*35L}{0.08206\frac{atm*L}{mol*K}*273.15K}\\\\n=1.56mol

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