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borishaifa [10]
3 years ago
7

A bathtub contains 45 gallons of water and the total weight of the tub and water is approximately 688.025 pounds. You pull the p

lug and the
water begins to drain
Let u represent the number of gallons of water that has drained from the tub since the plug was pulled. Note that water weights 8345 pounds per
gallon
a Write an expression in terms of u that represents the weight of the water that has drained from the tub (in pounds).
8.45v-688.025
Preview
b. Write an expression in terms of v that represents the total weight of the tub and water (in pounds).
1
Preview
c. How much does the tub weigh when there is no water in it?
* pounds
Preview
d. If the weight of the tub and water is 487.745 pounds, how many gallons of water have drained from the tub?
* gallons
Preview​
Mathematics
1 answer:
jolli1 [7]3 years ago
7 0

Answer:

a). 8.345v

b). 688.025 - 8.345v

c). 312.5 pounds

d). 21 gallons

Step-by-step explanation:

A bathtub contains amount of water = 45 gallons

And 1 gallon of water weighs = 8.345 pounds

Amount of water drained from the tub since the plug was pulled = v gallons

a) Therefore, weight of v gallons of water drained = 8.345v

b). Since total weight of the tub and water = 688.025 pounds

8.345v pounds of water is drained so total weight of tub and water will be = 688.025 - 8.345v

c). Total weight of the tub when v = 45 or the tub is empty.

Weight of the empty tub = 688.025 - 8.345(45)

= 688.025 - 375.525

= 312.5 pounds

d). If the weight of the tub and water is 487.745 pounds then we have to determine the amount of water drained from the tub.

Let the number gallons of water in the tub is w, then the weight of w gallons water = 8.345w pounds

Weight of the water and tub = weight of water + weight of the tub

487.745 = 8.345w + 312.5

8.345w = 487.745 - 312.5

8.345w = 175.245

w = \frac{175.45}{8.345}

w = 21 gallons

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