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rodikova [14]
4 years ago
10

Which sphere exists because of there is liquid iron as part of the earth's core?

Chemistry
2 answers:
Bingel [31]4 years ago
8 0
I think the answer is C.lithosphere. but i,m not 100% sure.
Feliz [49]4 years ago
4 0
The answer is the magnetosphere 
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A certain first-order reaction has a rate constant of 2.75 10-2 s−1 at 20.°c. what is the value of k at 45°c if ea = 75.5 kj/mol
Gekata [30.6K]

Answer:

0.314 s⁻¹  

Step-by-step explanation:

Use the <em>Arrhenius equation.</em>

\ln( \frac{k_2 }{k_1 }) = (\frac{E_{a} }{R })(\frac{ 1}{T_1} - \frac{1 }{T_2 })\\

Data:

k₁ = 0.0275 s⁻¹;            k₂ = ?

Eₐ = 75.5 kJ·mol⁻¹

T₁ = 20 °C = 293.15 K; T₂ = 45°C = 318.15 K

<em>Calculation: </em>

\ln(\frac{k_{2} }{0.0275}) = (\frac{75 500 }{8.314})(\frac{ 1}{293.15} - \frac{1 }{318.15 })

\ln(\frac{k_{2} }{0.0275}) = 9081\times 2.681 \times10^{-4}

\ln(\frac{k_{2} }{0.0275}) = 2.434

\frac{k_{2} }{0.0275} = \text{e}^{2.434}

\frac{k_{2} }{0.0275} = 11.41

k₂ = 0.0275 × 11.41

k₂ = 0.314 s⁻¹

3 0
3 years ago
Sample of gas occupies 10.0 L at 50 ˚C. Assuming that the pressure is constant what volume will
scZoUnD [109]

Answer:

<em>20 Liters</em>

Explanation:

If the pressure is supposed to be constant, one of Charles - Gay Lussac's laws can be used to solve the exercise. His statement says that "the volume of the gas is directly proportional to its temperature at constant pressure", mathematically it would be:

\frac{V1}{T1} = \frac{V2}{T2}

Considering T₁ = 50 ° C; V₁ = 10.0 L; and T₂ = 100 ° C, we can calculate the volume V₂ Clearing it from the equation and replacing the values to perform the calculation:

V2= (V1 x T2) / T1  = (10.0 L x  100°C)  / 50 °C = 20 L

Therefore, <em>the gas at 100 ° C will occupy a volume of 20.0 L</em>.

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3 years ago
In bullet points: explain the difference between thermal energy, heat and temperature.
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  • Temperature- is a measure of how hot or cold something is; specifically, a measure of the average kinetic energy of the particles in an object, which is a type of energy associated with motion.
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your answer is A  if i am wrong let me know

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True,I think.(so don't really count on my answer sorry :D)
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