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2 years ago

What process produces the sediments that ultimately lead to soil formation

Chemistry

2 answers:

NeTakaya2 years ago

7 0

Answer:

Hello! Your answer is Weathering.

Vikentia [17]2 years ago

6 0

The process by which rocks are broken down to form soil is called weathering. It is divided into 3 types, physical, chemical and biological weathering.
Physical weathering is the process by which rocks are broken down as a result of physical agitations. It is also called mechanical weathering and during this process the chemical nature of the rock is not affected. Biological weathering has to do with the weakening of rocks and their eventual disintegration as a result of plants and animals activities. Chemical weathering refers to the disintegration of the rock particles as a result of chemical reactions.

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Which of the following is an oxidation half-reaction?

Lilit [14]

Answer:

Sn²⁺ → Sn⁴⁺ + 2e⁻

Explanation:

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3 years ago

A sample of an unknown liquid has a mass of 21.09 g, and a volume of 6.44 ML. What is the density of this liquid?

Olenka [21]

Hey there!:

Mass = 21.09 g

Volume = 6.44 mL

Therefore;

Density = mass / Volume

Density = 21.09 / 6.44

Density = 3.274 g/mL

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2 years ago

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Crazy boy [7]

Answer:

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Explanation:

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2 years ago

Could a prokaryote have tissue , organs , and organ system ?

CaHeK987 [17]

Prokaryotes are usually unicellular - and so would not have tissue, organs or organ systems.Some prokaryotes are multicellular, and you could potentially say that they are a tissue (many similar cells working together to perform a task). However, no prokaryotes have organs or organ systems.

8 0

3 years ago

Read 2 more answers

To indicate the pH of a substance, one can use a dye that is both an acid and that appears as different colors in its protonated

PIT_PIT [208]

Answer:

<em>The pH of the solution is 7.8</em>

Explanation:

The concentration of the solution is 0.001M and the dye could be in its protonated and deprotonated forms. If the concentration of the protonated form [HA] is 0.0002 M the concentration of the deprotonated form will be the subtraction between the concentration of the bye and the concentration of the protonated form:

[A-] = 0.001M - 0.0002M = 0.0008M

Also, the Henderson-Hasselbalch equation is

$pH = pKa + Log \frac{[A^{-}]}{[HA]}$

this equation shows the dependency between the pH of the solution, the pKa and the concentration of the protonated and deprotonated forms. Thus, replacing in the equation

$pH = 7.2 + Log \frac{0.0008M}{0.0002M} = 7.8$

3 0

2 years ago