Water go through areas of high to low concentration in this case osmosis.
Answer:
V₂ = 290.3 cm³
Explanation:
Given data:
Initial pressure = 882 KPa
Initial volume = 312 cm³
Final pressure = 948 KPa
Final volume = ?
Solution:
The given problem will be solved through the Boly's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
882 KPa× 312 cm³ = 948 KPa × V₂
V₂ = 882 KPa× 312 cm³/ 948 KPa
V₂ = 290.3 cm³
What are you trying to ask
Answer:
2.5 L.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and T are constant, and have two different values of V and P:
<em>P₁V₁ = P₂V₂
</em>
P₁ = 5.0 atm, V₁ = 3.5 L.
P₂ = 7.0 atm, V₂ = ??? L.
<em>∴ V₂ = P₁V₁/P₂ </em>= (5.0 atm)(3.5 L)/(7.0 atm) = <em>2.5 L.
</em>