Answer:
Temperature required = 923K
Explanation:
The question is incomplete as there are some details that has to be given. details like the values of the standard enthalpies and entropies of the reactants and product as this is needed to calculate the actual value of the standard enthalpies and standard entropies of the reaction. I was able to get those values from literature and then calculated what needs to be calculated.
From there, I was able to use the equation that shows the relationship between, gibb's free energy, enthalpy, entropy and temperature. The necessary mathematical manipulation were done and the values were plugged in to get the temperature required to make the reaction spontaneous.
A few notes on the Gibb's free energy.
The Gibb's free energy also referred to as the gibb's function represented with letter G. it is the amount of useful work obtained from a system at constant temperature and pressure. The standard gibb's free energy on the other hand is a state function represented as Delta-G, as it depends on the initial and final states of the system.
The spontaneity of a reaction is explained by the standard gibb's free energy.
- If Delta-G = -ve ( the reaction is spontaneous)
- if Delta -G = +ve ( the reaction is non-spontaneous)
- if Delta-G = 0 ( the reaction is at equilibrium)
The step by step calculations is done as shown in the attachment.
Answer: 133,333.333 meters.
Explanation:
I forgot how to explain this looool.
Answer:
it would be 5,045
Explanation:
because it is closer to 5,000. pls correct me if wrong
Answer : The mass of
required is 18.238 grams.
Explanation : Given,
Mass of
= 83.10 g
Molar mass of
= 146 g/mole
Molar mass of
= 256.52 g/mole
The balanced chemical reaction is,

First we have to determine the moles of
.

Now we have to determine the moles of
.
From the balanced chemical reaction we conclude that,
As, 8 moles of
produced from 1 mole of 
So, 0.569 moles of
produced from
mole of 
Now we have to determine the mass of
.


Therefore, the mass of
required is 18.238 grams.