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yanalaym [24]
3 years ago
6

HHHEEEEEEELLLLPPPP PPPPPLLLLEEEASSSEEEE I GIVE ~BRAINLIEST~!!!!!! PLZ HELP ME

Chemistry
2 answers:
AnnyKZ [126]3 years ago
5 0
The action or power of focusing one's attention or mental effort.

a substance produced by a living organism that acts as a catalyst to bring about a specific biochemical reaction.


a substance that slows down or prevents a particular chemical reaction or other process, or that reduces the activity of a particular reactant, catalyst, or enzyme.
Anni [7]3 years ago
4 0
Concentration-The attention or power of focusing one's attention of mental effort.
Enzyme-Substance produced by living organism that acts as a catalyst to bring about a specific biochemical reaction
Inhibitor-Things that inhibits someone or something
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the bonding of two amino acids to form a larger molecule requires the addition of nitrogen the release of carbon dioxide the rel
Ksivusya [100]
What is the question here?

3 0
3 years ago
Please help on this question
natulia [17]
Send a more clearer picture...
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7 0
3 years ago
Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 4.1 g of butane is m
m_a_m_a [10]

Answer:

12.44 g

Explanation:

2C4H10 + 13O2 = 8CO2 + 10H2O

n(C4H10) = m(C4H10)/M(C4H10) = 4.1 / 58g/mol = 0.0707 mol (excess).

n(O2) = m(O2)/M(O2) = 25.9 / 32g/mol = 0.809 mol (deficiency).

Since the ratio of O2 to octane is 13 : 2 we can divide 0.0707 by 2 to get 0.03535 and divide 0.809 by 13 to get 0.062.

mass of CO2 produced =

M = [0.0707 moles C4H10 x 8 moles CO2] / 2 moles C4H10 x 44 g CO2/mol

M = 0.5656/2 * 44

M = 0.2828 * 44

M = 12.44 of CO2

5 0
3 years ago
If you assume this reaction is driven to completion because of the large excess of one ion, what is the concentration of [Fe(SCN
viktelen [127]

Answer : The concentration of [Fe(SCN)]^{2+} is, 4.32\times 10^{-4}M

Explanation :

When we assume this reaction is driven to completion because of the large excess of one ion then we are assuming limiting reagent is SCN^- and Fe^{3+} is excess reagent.

First we have to calculate the moles of KSCN.

\text{Moles of }KSCN=\text{Concentration of }KSCN\times \text{Volume of solution}

\text{Moles of }KSCN=0.00180M\times 0.006L=1.08\times 10^{-5}mol

Moles of KSCN = Moles of K^+ = Moles of SCN^- = 1.08\times 10^{-5}mol

Now we have to calculate the concentration of [Fe(SCN)]^{2+}

\text{Concentration of }[Fe(SCN)]^{2+}=\frac{\text{Moles of }[Fe(SCN)]^{2+}}{\text{Volume of solution}}

Total volume of solution = (6.00 + 5.00 + 14.00) = 25.00 mL = 0.025 L

\text{Concentration of }[Fe(SCN)]^{2+}=\frac{1.08\times 10^{-5}mol}{0.025L}=4.32\times 10^{-4}M

Thus, the concentration of [Fe(SCN)]^{2+} is, 4.32\times 10^{-4}M

7 0
3 years ago
What happens when Photographic film gets exposed to light?
AysviL [449]

Answer:

chyba  się zniszczy

Explanation:

ponieważ sie film prześwietli

8 0
3 years ago
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