Answer:
Option E is correct. none of the above is correct
Explanation:
Step 1: Data given
Solid Iron (III) = Fe^3+
iron (III) oxide = Fe2O3
Molar mass Fe = 55.845 g/mol
Molar mass Fe2O3 = 159.69 g/mol
Step 2: The balanced equation:
4Fe + 3O2 → 2Fe2O3
4 moles of iron will need 2 moles of oxygen gas to fully react
⇒ This is false 4 moles of iron will need 3 moles of oxygen gas to fully react
B.12 moles of iron, if reacted completely, can produce 8 moles of iron (III) oxide.
⇒ This is false: When 12 moles of iron completely react, we can produce 12/2 = 6 moles of Fe2O3
C.9 moles of oxygen can produce 9 moles of Iron (III) oxide
⇒ This is false; 9 moles of O2 can produce 6 moles of Fe2O3
D.6 moles of oxygen can react completely to produce 6 moles of iron (III) oxide.
⇒ This is false 6 moles of O2 will react completely to produce 4 moles of Fe2O3
E.none of the above
Answer:
Neutral
Explanation:
A pH of 7 is neutral. A pH less than 7 is acidic. A pH greater than 7 is basic. The pH scale is logarithmic and as a result, each whole pH value below 7 is ten times more acidic than the next higher value.
No porque plantas estan vivas pero no se mueven solo.
<em>V= 110mL = 110cm³ = 0,11dm³</em>
<em>C = 1,244 mol/L = 1,244 mol/dm³</em>
C = n/V
n = 1,244×0,11
<u>n = 0,13684 moles</u>
<em>mCa(OH)₂ = 74 g/mol</em>
1 mole Ca(OH)₂ ------------ 74g
0,13684 ---------------------- X
X = 74×0,13684
<u>X = 10,12616g</u>
:)
Answer:
58.0 g of MgO
Explanation:
in a perfect world, 70 g, however we don't live in a perfect world
The equation of reaction
2Mg + O₂ --> 2MgO
first find which element is limiting:
35 g x 1 mol/24.3 g of Mg x 2 mol of MgO/ 2 mole of Mg = 1.44 moles of MgO
35 g x 1 mol/32g of Mg x 2 mol of MgO/ 1 mole of O₂ = 2.1875 moles of MgO
This means Mg is the limiting factor, so you will be using this moles to find grams of MgO
1.44 mols of MgO x 40.3 g of MgO/ 1 mol = 58.0 g of MgO
