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Alenkasestr [34]
3 years ago
5

A ____________ is a chemical solution that keeps ph within normal limits by absorbing excess hydrogen, or h+, ions and hydroxide

, or oh-, ions.
Chemistry
2 answers:
garri49 [273]3 years ago
8 0

Answer:

Buffer.

Explanation:

A buffer solution is a solution made out of a weak acid/base and its conjulgated base/acid. This kind of solution is special because it is resistent so pH change because it can react with acids and with bases, thus it keep pH withing a determined range as long as it is not fully consumed by excess adition of acid/base.

TiliK225 [7]3 years ago
5 0
its a buffer solution
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How do the valence electrons of an element determine how they will combine with other elements to produce a compound? Please hel
Vlad1618 [11]

Answer:

See explanation

Explanation:

The valence electrons are electrons found on the valence (outermost) shell of an atom.

When an atoms form compounds, there is an exchange of valence electrons between the atoms of one element and the atoms of another element.

Let us consider a typical example, sodium has one valence electron and chlorine has seven valence electrons. This means that chlorine needs one electron to complete its octet while sodium needs to release one electron in order to attain the octet structure.

So, sodium gives out its one electron and becomes a stable sodium ion and chlorine accepts that electron and becomes a stable chloride ion. This is how the compound sodium chloride is formed.

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2 years ago
Silver tarnish consists of silver sulfide. what is its chemical formula?
Andreyy89
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3 years ago
Is an element’s flame color a chemical characteristic? Explain.
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Answer:

It's a physical property because color is chemically not significant.

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2 years ago
Convert 25 gram of carbon dioxide to mold
Rus_ich [418]

The atomic weight of carbon dioxide is about 12.011 + 15.999 + 15.999 = 44.009.

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3 years ago
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morpeh [17]

T eg(1) : 97.5°C, T eg(2): 98.5°C, T eg(3): 99.2°C

∆T water(1): -2.5°C, ∆T water(2): -1.5°C, ∆T water(3): -0.8°C

∆T metal(1): 77.5°C, ∆T metal(2): 80.5°C, ∆T metal(3): 80.2°C.

ft= (m1 cp1 t1 + m2 cp2 t2 + .... + mn cpn tn) / (m1 cp1 + m2 cp2 + .... + mn cpn) (1)

where,

1000g = 1kg

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m = mass of substance (kg)

cp = specific heat of substance (J/kg°C)

t = temperature of substance (°C)

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3 years ago
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