A 9.35g sample of a solid was placed in a 15.00mL flask. The remaining volume was filled with Benzene in which the solid is inso
2 answers:
Answer: 1.58 g/ml
Explanation:
Given :Total mass= 17.33 g
Mas of solid = 9.35 g
Thus Mass of benzene = Total mass - Mass of solid= (17.33-9.35)g= 7.98 g
Density of benzene = 0.876 g/ml
Therefore Volume of benzene =
Total volume = 15 ml
Volume of solid = Total volume - Volume of benzene= (15-9.1)=5.9ml
Thus Density of solid=
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I have attached the diagram related to this question.
Answer:
5A₂ + 5B .................> 4A₂B + A₂ + B
Explanation:
1- For the reactants:
We can note that:
i- we have 5 moles of substance A which is diatomic. This means that we have 5A₂
ii- we have 5 moles of substance B which is monoatomic. This means that we have 5B
Based on the above, for the reactants side, we have:
5A₂ + 5B
2- For the products:
We can note that:
i- we have 4 moles of a substance formed from the combination of two moles of substance A with one mole of substance B. This means that we have 4A₂B
ii- we have one mole of substance A that is diatomic. This means that we have A₂
iii- we have one mole of substance B that is monoatomic. This means that we have B
Based on the above, for the products side, we have:
4A₂B + A₂ + B
3- Combining reactants and products parts:
Combining the reactants side (from part 1) with the products side (from part 2), we can find that the initial equation is as follows:
5A₂ + 5B .................> 4A₂B + A₂ + B
4- Balancing the equation:
Taking a look at the initial equation we reached in part 3, we will find that:
Number of moles of substance A in reactants = 2*5 = 10 moles
Number of moles of substance A in products = 2*4 + 2*! = 10 moles
SUBSTANCE A IS BALANCED
Number of moles of substance B in reactants = 5*1 = 5 moles
Number of moles of substance B in products = 4*1 + 1 = 5 moles
SUBSTANCE B IS BALANCED
Based on the above, the final balanced equation is the same as the initial equation reached in part 3:
5A₂ + 5B .................> 4A₂B + A₂ + B
Hope this helps :)
Answer:
5A₂ + 5B .................> 4A₂B + A₂ + B
Explanation:
1- For the reactants:
We can note that:
i- we have 5 moles of substance A which is diatomic. This means that we have 5A₂
ii- we have 5 moles of substance B which is monoatomic. This means that we have 5B
Based on the above, for the reactants side, we have:
5A₂ + 5B
2- For the products:
We can note that:
i- we have 4 moles of a substance formed from the combination of two moles of substance A with one mole of substance B. This means that we have 4A₂B
ii- we have one mole of substance A that is diatomic. This means that we have A₂
iii- we have one mole of substance B that is monoatomic. This means that we have B
Based on the above, for the products side, we have:
4A₂B + A₂ + B
3- Combining reactants and products parts:
Combining the reactants side (from part 1) with the products side (from part 2), we can find that the initial equation is as follows:
5A₂ + 5B .................> 4A₂B + A₂ + B
4- Balancing the equation:
Taking a look at the initial equation we reached in part 3, we will find that:
Number of moles of substance A in reactants = 2*5 = 10 moles
Number of moles of substance A in products = 2*4 + 2*! = 10 moles
SUBSTANCE A IS BALANCED
Number of moles of substance B in reactants = 5*1 = 5 moles
Number of moles of substance B in products = 4*1 + 1 = 5 moles
SUBSTANCE B IS BALANCED
Based on the above, the final balanced equation is the same as the initial equation reached in part 3:
5A₂ + 5B .................> 4A₂B + A₂ + B
Hope this helps :)
Answer:
Explanation:
The objective of this question is all about identifying the phenomena that holds true for the statement being said in each instance. Let; walk through them.
a) Whenever you see 9 or a multiple of 9 in the integration ratio, which group should you first consider for being responsible for that signal.
( C₄H₉ )Tert. Butyl group
b) Whenever you see a quartet and triplet on a spectrum, which group should you first consider for being responsible for those signals?
(CH₃CH₂) ethyl group
c) Whenever you see septet and a doublet on a spectrum, which group should you first consider for being responsible for those signals?
(CH(CH₃)₂) isoproply group
d) Whenever you see 6 or a multiple of 6 in the integration ratio, which group should you first consider for being responsible for that signal
(CH(CH₃)₂) isoproply group
e) Whenever you see 3 as the actual number of protons for a given signal, which group should you first consider for being responsible for that signal.
CH₃- methyl group
A perfect description showing the explanation of each answers chosen is explained with an aid of diagram below.
A 50.0 ml sample of 0.108 m h2so4 is diluted to 250.0 ml. Its new molarity will be 0.0216 m.
Dilution would be the process of lowering a solute's concentration in a solution. It usually just includes combining the solution with much more solvent, such as water. A solution is diluted when more solvent is added without increasing solute.
Molarity can be calculated by using the formula:
where, M is molarity and V is volume.
Given data:
= 0.108 m
= 50 ml
= 250 ml
Put the value of given data in above equation.
0.108 m × 50 ml = M × 250ml
M = 0.0216 m
Therefore, the new molarity will be 0.0216 m.
To know more about molarity
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