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1 year ago

Question 14 of 25

2 answers:

5 0

A. Areas within an energy level that are occupied by electrons

There are different energy levels where electrons (probably) are, they are hanging out in the orbitals, or energy levels around the nucleus.

We know the other options are wrong because protons are in the nucleus of an atom, neutrons have a neutral charge, and although B sounds right, A is the more accurate choice

algol131 year ago

3 0

Answer:

describes properties characteristic of no more than two electrons in the vicinity of an atomic nucleus or of a system of nuclei as in a molecule

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Which example best shows conservation of resources?

zaharov [31]

Answer:

Explanation:

I took this test as a freshman and this was the only question of 4 that I can remember

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3 years ago

Read 2 more answers

5) 3Na2SO4

xenn [34]

Answer:

3Na2SO4

Explanation:

3Na2SO4

# of molecules: 3 moles of Na2SO4 or 3 × 6.22 × 10^23 molecules.

# of elements: 3 elements l

Name of element: = Sodium, S = Sulphur, O = Oxygen

# of atoms: Na = 6 atoms, S= 3, O= 12

Total # of atoms: 21

The #3 is a Coefficient.

Please mark branliest if you are satisfied. Thanking in anticipation.

7 0

2 years ago

Convert 67 inches into a feet

fiasKO [112]

Answer:

Explanation:every feet has 12in so divde, 67/12 so its 5ft 7/12

4 0

2 years ago

Write the molecular formula of nitrate using criss cross method

exis [7]

Answer:

NO3 that is the answer to the question

8 0

2 years ago

Antarctica, almost completely covered in ice, has an area

Marysya12 [62]

Answer: The mass of ice is $2.39\times 10^{22}g$

Explanation:

We are given:

Area of Antarctica = $5,500,000mi^2=5,500,000\times 2.59\times 10^{10}=142.45\times 10^{15}cm^2$ (Conversion factor: $1mi^2=2.59\times 10^{10}cm^2$ )

Height of Antarctica with ice = 7500 ft.

Height of Antarctica without ice = 1500 ft.

Height of ice = 7500 - 1500 = 6000 ft = $182.88\times 10^3cm$ (Conversion factor: 1 ft = 30.48 cm)

To calculate mass of ice, we use the equation:

$\text{Density of a substance}=\frac{\text{Mass of a substance}}{\text{Volume of a substance}}$

We are given:

Density of ice = $0.917g/cm^3$

Volume of ice = Area × Height of ice = $142.45\times 10^{15}cm^2\times 182.88\times 10^3cm=26051.26\times 10^{18}cm^3$

Putting values in above equation, we get:

$0.917g/cm^3=\frac{\text{Mass of ice}}{26051.26\times 10^{18}cm^3}\\\\\text{Mass of ice}=(0.917g/cm^3\times 26051.26\times 10^{18}cm^3=2.39\times 10^{22}g$

Hence, the mass of ice is $2.39\times 10^{22}g$

5 0

2 years ago