Answer:
σ = 4.998 E-4 C/m²
Explanation:
- 1 Coulomb (C) ≡ 6.241509 E18 electrons (e)
∴ # elect = 6.24 E14 elect
charge (Q):
⇒ Q = (6.24 E14 elect)/( 1 C /6.241509 E18 elect) = 9.998 E-5 C
charge density (σ):
∴ surface area (S) = 0.2 m²
⇒ σ = ( 9.998 E-5 C ) / ( 0.2 m²)
⇒ σ = 4.998 E-4 C/m²
The amount of sugar is 2621 mg
Why?
The complete question is:
A 12.630 g milk chocolate bar is found to contain 8.315 g of sugar.
Part B. What will be the amount of sugar in milligrams if the size of the milk chocolate bar is reduced from 12.630 g to 4.000 g ?
To find the answer we have to determine first the amount of sugar in milligrams per gram of chocolate bar. We can find that by applying the following conversion factor:
Now, we have to determine the amount of sugar in milligrams if we had a chocolate bar with 4.000 g:
Have a nice day!
London dispersion
dipole-dipole
Answer:
Option 2= Glucose
Explanation:
Cell membrane is made up of two phospholipid layers and each contain phosphate head and fatty acid or lipid tails. the head is present between the outer and inner boundaries and tail is present in between. The small non- polar molecules can pass the membrane through simple diffusion. This lipid tail restrict the passage of polar molecules including water soluble substances like glucose. However, transmembranes are present that allow the molecules to inter that are blocked by the tails.
Facilitated diffusion:
it is a type of diffusion in which caries protein without using the cellular energy shuttle the molecules to the cell membrane. Glucose is bind on the carrier protein ,change the shape and transport it from one to another side of membrane. In order to absorb the glucose red blood cells use this kind of diffusion.
Primary active transport:
The cells that are present along small intestine use this type of transport to pump the glucose inside the cell. The primary active transport require energy to transport the glucose inside.
Secondary active transport:
It is another method of transport of glucose into the cell. This method can not use ATP but it is based on concentration gradient of the sodium that provide electro chemical energy for the glucose transport.
