Answer:
The recoil speed of Astronaut A is 0.26 m/s.
Explanation:
Given that,
Mass of astronaut A,
Mass of astronaut B,
Astronaut A pushes B away, with B attaining a final speed of 0.4,
We need to find the recoil speed of astronaut A. The momentum remains conserved here. Using the law of conservation of linear momentum as :
So, the recoil speed of Astronaut A is 0.26 m/s.
Answer:
Explanation:
give,
Gauge pressure of car, P₁ = 30 psi
temperature,T₁ = 0° C = 0 + 273 = 273 K
Assuming temperature at the noon = 30° C
T₂ = 30 + 273 = 303 K
Pressure at this temperature, P₂ = ?
Using ideal gas equation
taking volume as in compressible V₁ = V₂
Hence, Pressure of the at 30°C is equal to 33.297 psi.
Answer:
(a) T = 2987.6 k
(b) T = 19986.2 k
Explanation:
The temperature of a star in terms of peak wavelength can be given by Wein's Displacement Law, which is as follows:
where,
T = Radiated surface temperature
= peak wavelength
(a)
here,
= 970 nm = 9.7 x 10⁻⁷ m
Therefore,
<u>T = 2987.6 k</u>
(b)
here,
= 145 nm = 1.45 x 10⁻⁷ m
Therefore,
<u>T = 19986.2 k</u>