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elena-14-01-66 [18.8K]
3 years ago
14

Uuuuuuuuuuuuuuuuuummmmmmmmmmmmmmmmmmmm help

Physics
2 answers:
tatiyna3 years ago
3 0
I think it 32, but i’m not sure
ddd [48]3 years ago
3 0
Answer: sixteen
reasoning: yes
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Explain what physicists mean when they say that the de Broglie wavelength relates to the probability distribution wave function.
Ksju [112]

Answer:

Because it unites particle and wave nature.

Explanation:

De Broglie wavelength can be defined as the,

\lambda =\frac{h}{mv}

Here, h is planks constant, m is the mass of electron, v is the velocity of electron.

Since the de Broglie wavelength can behave like the photon wavelength with respect to the  momentum

It unites particles and waves nature ,so De Broglie wavelengths is probability waves associated with the wave function according to physicists.

7 0
3 years ago
What is the area of 12 1/2 and 17 1/5
jonny [76]
215

I am assuming that those are the width and length. So to find area all you have to do is multiply the two because lw = a. 12 1/2*17 1/5 = 215

25/2*86/5 = 2150/10 = 215
3 0
3 years ago
The speed of light in a vacuum is 3 x 108 miles/hour. true/false?
GarryVolchara [31]
I'm guessing they rounded because it is technically 2.998 X 108 miles/hour

so I would go with true!
8 0
3 years ago
Read 2 more answers
Now assume that Eq. 6-14 gives the magnitude of the air drag force on the typical 20 kg stone, which presents to the wind a vert
chubhunter [2.5K]

Answer:

362.41 km/h

Explanation:

F = Force

m = Mass = 84 kg

g = Acceleration due to gravity = 9.81 m/s²

C = Drag coefficient = 0.8

ρ = Density of air = 1.21 kg/m³

A = Surface area = 0.04 m²

v = Terminal velocity

F = ma

F=\frac{1}{2}\rho CAv^2\\\Rightarrow mg=\frac{1}{2}\rho CAv^2\\\Rightarrow v=\sqrt{2\frac{mg}{\rho CA}}\\\Rightarrow v=\sqrt{2\frac{20\times 9.81}{1.21\times 0.8\times 0.04}}\\\Rightarrow v=100.66924\ m/s

Converting to km/h

100.66924\times 3.6=362.41\ km/h

The terminal velocity of the stone is 362.41 km/h

5 0
3 years ago
Read 2 more answers
A weightlifter lifts a 250-kg mass 0.5 meters above his head, how much PEg does the mass have (Note: g=9.8 m/s2)? Round your ans
morpeh [17]

Answer:

1225 J

Explanation:

The Gravitational potential energy (PEG) gained by a mass lifted above the ground is given by

PE=mgh

where

m is the mass

g = 9.8 m/s^2 is the acceleration due to gravity

h is the height at which the object has been lifted

In this problem, we have

m = 250 kg

h = 0.5 m

So, the PE of the object is

PE=(250 kg)(9.8 m/s^2)(0.5 m)=1225 J

6 0
3 years ago
Read 2 more answers
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