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dangina [55]
4 years ago
5

A power station delivers 510 kw of power at 12,000 v to a factory through wires of total resistance of 2.5 ω. how much less powe

r is wasted if the electricity is delivered at 47,000 v rather than 12,000 v?
Physics
1 answer:
bixtya [17]4 years ago
3 0

The currents (Amperes) in the two cases are calculated as power/voltage: <span>

510000W / 12000V = 42.5 A 
510000W / 47000V = 10.85 A 

<span>And that the power wasted in the two cases is calculated as current^2 x resistance:

(42.5 A)^2 (2.5 Ohms) = 4,515.625 W 
(10.85 A)^2 (2.5 Ohms) = 294.30625 W 

<span>So the amount of power saved is the difference:
<span>4,515.625 - 294.30625  = 4221.32 Watts</span></span></span></span>

<span>This is the main reason why distribution grids aim to operate at the highest voltages possible.</span>

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Make Neptune closer to the sun because then it would have a stronger gravitation pull. Because the closer the objects are, they will have a stronger gravitaional force and when the object has more mass, the gravity is also stronger. So, if the mass is reduced, the gravity force would be reduced, but if you bring neptune closer, the gravity force would increase
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Does the Earth stay in one place throughout the year? If it doesn't, describe its motion and where it's located in the solar syt
stiv31 [10]

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6 0
3 years ago
A contestant in a winter games event pulls a 36.0 kg block of ice across a frozen lake with a rope over his shoulder as shown in
Novay_Z [31]

(a) The minimum force F he must exert to get the block moving is 38.9 N.

(b) The acceleration of the block is 0.79 m/s².

<h3>Minimum force to be applied </h3>

The minimum force F he must exert to get the block moving is calculated as follows;

Fcosθ = μ(s)Fₙ

Fcosθ = μ(s)mg

where;

  • μ(s) is coefficient of static friction
  • m is mass of the block
  • g is acceleration due to gravity

F = [0.1(36)(9.8)] / [(cos(25)]

F = 38.9 N

<h3>Acceleration of the block</h3>

F(net) = 38.9 - (0.03 x 36 x 9.8) = 28.32

a = F(net)/m

a = 28.32/36

a = 0.79 m/s²

Thus, the minimum force F he must exert to get the block moving is 38.9 N.

The acceleration of the block is 0.79 m/s².

Learn more about minimum force here: brainly.com/question/14353320

#SPJ1

4 0
2 years ago
Many industries are powered via distant power stations. Calculate the current flowing through a 7,300m long 10. copper power lin
Oliga [24]

Answer:

Current, I = 1000 A

Explanation:

It is given that,

Length of the copper wire, l = 7300 m

Resistance of copper line, R = 10 ohms

Magnetic field, B = 0.1 T

\mu_o=4\pi \times 10^{-7}\ T-m/A

Resistivity, \rho=1.72\times 10^{-8}\ \Omega-m

We need to find the current flowing the copper wire. Firstly, we need to find the radius of he power line using physical dimensions as :

R=\rho \dfrac{l}{A}

R=\rho \dfrac{l}{\pi r^2}

r=\sqrt{\dfrac{\rho l}{R\pi}}

r=\sqrt{\dfrac{1.72\times 10^{-8}\times 7300}{10\pi}}

r = 0.00199 m

or

r=1.99\times 10^{-3}\ m=2\times 10^{-3}\ m

The magnetic field on a current carrying wire is given by :

B=\dfrac{\mu_o I}{2\pi r}

I=\dfrac{2\pi rB}{\mu_o}

I=\dfrac{2\pi \times 0.1\times 2\times 10^{-3}}{4\pi \times 10^{-7}}

I = 1000 A

So, the current of 1000 A is flowing through the copper wire. Hence, this is the required solution.

4 0
3 years ago
PLEASE HELPPP Count the number of atoms of each element in this molecule: 2H2K(OH2)2​
yulyashka [42]

Answer:

H = 6 atoms

K= 2 atoms

O = 2 atoms

7 0
3 years ago
Read 2 more answers
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