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dangina [55]
3 years ago
5

A power station delivers 510 kw of power at 12,000 v to a factory through wires of total resistance of 2.5 ω. how much less powe

r is wasted if the electricity is delivered at 47,000 v rather than 12,000 v?
Physics
1 answer:
bixtya [17]3 years ago
3 0

The currents (Amperes) in the two cases are calculated as power/voltage: <span>

510000W / 12000V = 42.5 A 
510000W / 47000V = 10.85 A 

<span>And that the power wasted in the two cases is calculated as current^2 x resistance:

(42.5 A)^2 (2.5 Ohms) = 4,515.625 W 
(10.85 A)^2 (2.5 Ohms) = 294.30625 W 

<span>So the amount of power saved is the difference:
<span>4,515.625 - 294.30625  = 4221.32 Watts</span></span></span></span>

<span>This is the main reason why distribution grids aim to operate at the highest voltages possible.</span>

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I hope my answer has come to your help. Thank you for posting your question here in Brainly.
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