A football wide receiver rushes 16 m straight down the playing field in 2.9 s (in the positive direction). He is then hit and pu
shed 2.5 m straight backwards in 1.65 s. He breaks the tackle and runs straight forward another 24 m in 5.2 s. Part (a) Calculate the wide receiver's average velocity in the horizontal direction during the first interval, in meters per second.
Part (b) Calculate the wide receiver's average velocity in the horizontal direction during the second interval, in meters per second.
Part (c) Calculate the wide receiver's average velocity in the horizontal direction during the third interval, in meters per second.
Part (d) Calculate the wide receiver's average velocity in the horizontal direction for the entire motion, in meters per second
This question can be better understood when discussed using the Newton's first law of motion which states that an object would continue to move with a uniform speed (in a straight line) unless acted upon by an external force. What happens here (in the question) is that the bike rider would have continued moving at a constant speed (to the right) if not for the opposing force of the wind that acted against her (to the left). <u>This wind/force would cause her speed to reduce or slow down (as posited by the law)</u>.
Divide 10000m by 160m/min, you will get the answer 62.5. You then subtract 12.5 from 62.5 to understand what you will need your answer for the other person’s speed will be. 10000m divided by 50min is 200m/min.
