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3 years ago

Which quantity is a scalar quantity?

Physics

1 answer:

kow [346]3 years ago

3 0

Answer:

area is the scalar quantity

Explanation:

Scalar quantity are those which only have magnitude and no direction.

For example: mass, time, distance etc.

Vector quantity are those which have both magnitude and direction.

For example: displacement , velocity etc.

From the given options, the quantity which is scalar is are a because it only has magnitude but no directions.

Where acceleration, velocity, displacement and force all are vector quantities., the correct answer is option B.

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What is the minimum body mass index for obesity

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A 91.1 kg horizontal circular platform rotates freely with no friction about its center at an initial angular velocity of 1.73 r

KIM [24]

Answer:

$\omega_f = 1.08 rad/s$

Explanation:

As we know that there is no external torque on the system of platform, banana and the monkey

so the angular momentum of the system will remains conserved

so here we can say

$L_i = L_f$

$I_o\omega = (I_o + m_1r_1^2 + m_2r_2^2)\omega_f$

here we know that

$I_o = \frac{1}{2}mR^2$

$I_o = \frac{1}{2}(91.1)(1.61)^2 = 118.1 kg m^2$

$m_1 = 9.41 kg$

$r_1 = \frac{4}{5}(1.61) = 1.29 m$

$m_2 = 21.1 kg$

Now from above equation

$118.1(1.73) = (118.1 + 9.41(1.29^2) + 21.1(1.61^2))\omega_f$

$118.1(1.73) = 188.45\omega_f$

$\omega_f = 1.08 rad/s$

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3 years ago

A puddle of water has a thin film of gasoline floating on it. A beam of light is shining perpendicular on the film. If the wavel

g100num [7]

Answer:

option A

Explanation:

Given,

wavelength of light, $\lambda = 560\ nm$

refractive index of gasoline, n₁ = 1.40

Refractive index of water, n₂ = 1.33

thickness of the film, t = ?

Condition of constructive interference is given by

$2 n t = (m+\dfrac{1}{2})\lambda$

For minimum thickness of the film m = 0

From the question we can clearly observe that phase change from gasoline to air

so, n = 1.4

$2 \times 1.4 \times t = \dfrac{560}{2}$

$t = 100\ nm$

Hence, the correct answer is option A

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4 years ago

A spherical snowball is melting in such a way that its radius is decreasing at rate of 0.1 cm/min. At what rate is the volume of

andrew11 [14]

Answer:

$\frac{dV}{dt}=-78,4\pi \frac{cm^{3} }{min}$

Explanation:

Knowing that the volume of a sphere is V=(4/3)πr³ and $\frac{dr}{dt}=-0.1\frac{cm}{min}$

We must find $\frac{dV}{dt}=?$ when r=14cm

V=(4/3)πr³ ⇒

$\frac{dV}{dt}=\frac{4}{3}\pi3r^{2}\frac{dr}{dt}\\\frac{dV}{dt}=4\pi r^{2}(-0.1\frac{cm}{min})$

and r=14cm then

$\frac{dV}{dt}=4\pi(14cm)^{2}(-0.1\frac{cm}{min})\\\frac{dV}{dt}=4\pi196cm^{2}(-0.1\frac{cm}{min})\\\frac{dV}{dt}=-78,4\pi \frac{cm^{3} }{min}$

Note: as you can see the relationship of change of r with respect to t is negative because it is a decrease, and also its volume ratio

4 0

4 years ago