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Ilya [14]
3 years ago
14

Shalina uses the expression 3x to determine the cost of x notebooks. What is the cost of 24 notebooks?

Mathematics
2 answers:
professor190 [17]3 years ago
5 0

Answer:

72 money

Step-by-step explanation:

Alexxx [7]3 years ago
3 0
3x is the cost for x notebooks
24*3 is the cost of 24 notebooks
that is 24*3=72
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(25 + 19) + 15 = (19 + 25) + 15<br><br><br> What property is that equation
malfutka [58]

Answer:

Commutative Property

Step-by-step explanation:

It looks like Associative property which is when you change the GROUP, but actually it’s commutative because it didn’t change any numbers in the group, just the order of where they were.

Associative: (25 + 19) + 15 = (15 + 19) + 25

Commutative: (25 + 19) + 15 = (19 + 25) + 15

It didn’t change the numbers, only the order. Therefore, it would be commutative property

8 0
3 years ago
Read 2 more answers
Solve for x:<br> 7x + 5 + x - 3 + x = 5
Soloha48 [4]

Answer:

x=1/3

Step-by-step explanation:

9x+5-3=5

9x=3

x=1/3

6 0
3 years ago
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Write an equation in slope-intercept form for the line that passes through the
Pavlova-9 [17]
Make slope intercept
3x - y = 5
3x = y + 5
y = 3x - 5
Parallel = same slope
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Y = 3x + b
Plug in the point
-2 = 3(-1) + b
-2 = -3 + b, b = 1

Solution: y = 3x + 1
6 0
3 years ago
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Which of the following can be used to show that these triangles are congruent?
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8 0
2 years ago
A population of insects grows exponentially, as shown in the table. Suppose the increase in population continues at the same rat
Ivanshal [37]

We are told that a population of insects grows exponentially and we are given a table of data about insect population growth. We are asked to find population of insects at the end of week 11.        

The initial insect population is 20 and at the end of 1st week population increases to 30.

Let us find growth percentage of insect  population,

\text{Growth percentage}=\frac{\text{Difference}}{Actual} \cdot100

\text{Growth percentage}=\frac{\text{30-20}}{20} \cdot100

\text{Growth percentage}=\frac{\text{10}}{20} \cdot100

\text{Growth percentage}=0.5 \cdot100=50

We can see that insect population is growing at rate of 50% per week.

Now let us write an exponential function for our population.

P(w)=20(1+0.50)^{w}, where P(w) represents population at the end of w weeks.

Let us substitute w=11 in our function to find insect population at the end of 11 weeks.

P(11)=20(1+0.50)^{11}

P(11)=20(1.50)^{11}

P(11)=20\cdot 86.49755859375

P(11)=1729.951171875\approx 1730

Therefore, population of insects at the end of 11th week will be 1730.  



7 0
3 years ago
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