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inysia [295]
3 years ago
6

Explain how to choose a proper indicator in an acid-base titration such as adding a strong acid (HCI) to a strong base (NaOH) ,

a strong acid (HCI) to a weak base (NH3) and s strong base (NaOH) to a weak acid (CH3COOH).
Chemistry
1 answer:
Jet001 [13]3 years ago
5 0
The pH of the solution at equivalence point is dependent on the strength of the acid and strength of the base used in the titration.

For strong acid-strong base titration, pH = 7 at equivalence point
For weak acid-strong base titration, pH > 7 at equivalence point
For strong acid-weak base titration, pH < 7 at equivalence point

https://www.khanacademy.org/test-prep/mcat/chemical-processes/titrations-and-solubility-equilibria/a...  

The indicator changes color when the pH changes at the endpoint of the titration. So, you need to determine what is present at the point and find the pH at the point. Then, you can reference a table of indicators to choose one whose color will change over the pH that includes your equivalency point.
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Combustion of 9.511 grams of c4h10 will yield ____ grams of CO2
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\boxed{28.81}

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We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:      58.12                   44.01

           2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O

m/g:     9.511

1. Moles of C₄H₁₀

\text{Moles of C$_{4}$H$_{10} $} = \text{ 9.511 g C$_{4}$H$_{10} $} \times \dfrac{\text{1 mol C$_{4}$H$_{10} $}}{\text{ 58.12 g C$_{4}$H$_{10} $}} = \text{0.1636 mol C$_{4}$H$_{10}$}

2. Moles of CO₂

The molar ratio is 8 mol CO₂:2 mol C₄H₁₀

\text{Moles of CO}_{2} =\text{0.1636 mol C$_{4}$H$_{10} $} \times \dfrac{\text{8 mol CO}_{2}}{\text{2 mol C$_{4}$H$_{10}$}} = \text{0.6546 mol CO}_{2}

3. Mass of CO₂

\text{Mass of CO}_{2} = \text{0.6546 mol CO}_{2} \times \dfrac{\text{44.01 g CO}_{2}}{\text{1 mol CO}_{2}} = \textbf{28.81 g CO}_{2}\\\\\text{The combustion will form $\boxed{\textbf{28.81 g CO}_{2}}$}

8 0
3 years ago
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