Ask question

Ask question

All categories

3 years ago

13

How many moles of sulfuric acid (H2SO4) are needed to react completely with 6.8 moles of lithium hydroxide (LiOH)? (4 points) 2L

iOH + H2SO4 → Li2SO4 + 2H2O

1 answer:

Keith_Richards [23]3 years ago

3 0

Answer:

3.4 mol H2SO4

Explanation:

Took the test

You might be interested in

PLS HELP NEED ANSWER what is the difference between water and water molcules

dimaraw [331]

Answer:

One molecule of water has two hydrogen atoms covalently bonded to a single oxygen atom. Water is a tasteless, odorless liquid at ambient temperature and pressure.

Explanation:

Hope this helps :) Have a great day!

4 0

2 years ago

When a star dies which of these celestial objects is it most likely to help create ?

Naily [24]

The answer is B.) a star

did this help?

8 0

3 years ago

Read 2 more answers

2 SO3 (g) + Heat <-----> 2 SO2 (g) + O2 (g)

Step2247 [10]

Answer:

The concentration of SO₂ will decreases

Explanation:

As you can see in the reaction

2 moles of gas ⇆ 3 moles of gas

Based on Le Châtelier's principle, a change doing in a system will produce that the system reacts in order to counteract the change made.

If the pressure is increased, the system will shift to the left in order to produce less moles of gas and decrease, thus, the pressure.

As the system shift to the left, the concentration of SO₂ will decreases

7 0

3 years ago

The molarity of a sodium hydroxide (NaOH) solution is 0.2 M. The molar mass of NaOH is 40 g/mol. If the solution contains 20 g o

mote1985 [20]

Answer:

$\large \boxed{\text{2.5 L}}$

Explanation:

1. Calculate the moles of NaOH.

$\text{Moles} = \text{20 g} \times \dfrac{\text{1 mol}}{\text{40 g}} = \text{0.50 mol}$

2. Calculate the volume of NaOH

$\begin{array}{rcl}\\\text{Molar concentration} &= &\dfrac{\text{moles}}{\text{litres}}\\\\ n &= &\dfrac{c}{V}\\\\\dfrac{\text{0.2 mol}}{\text{1 L}} &=& \dfrac{\text{0.50 mol}}{V}\\\\ \dfrac{0.2V}{\text{1 L}} & = & 0.50\\\\0.2V &= & \text{0.50 L}\\V & = & \dfrac{\text{0.50 L}}{0.2}\\\\& = & \textbf{2.5 L}\\\end{array}\\\text{The volume of the solution is $\large \boxed{\textbf{2.5 L}}$}$

7 0

3 years ago

Read 2 more answers

The atomic mass and abundance of Cr-50 is 49.946 amu and 4.3%. The atomic mass and abundance of Cr-52 is 51.941 amu and 83.8%. T

Sati [7]

Multiply the mass by the abundance and add each. Make sure to convert the percentage into a decimal. (49.946 * .043) + (51.941 * .838) + (52.941 * .095) + (53.939 * .024) = 51.99 round up using sig figs and the answer is c. 52.00 amu

6 0

2 years ago