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Ket [755]
3 years ago
5

Formula of acetic acid & sodium acetate

Chemistry
1 answer:
ki77a [65]3 years ago
4 0

Answer:

<h3>(CH3COOH + <u>CH3COONa</u><u>)</u></h3>

<u>this</u><u> </u><u>is</u><u> </u><u>the</u><u> </u><u>answer</u>

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Help I Will Mark Brainlist !! (ATTACHED IMAGE BELOW) Which of the diagrams below would be the FASTEST? _____ Why? Which of the d
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Answer:

Fastest C. Reaction time is faster

Slowest A. Reaction time is slower and it takes longer to finish

Explanation:

4 0
2 years ago
The vapor pressure of the liquid NH3 is measured at different temperatures. The following vapor pressure data are obtained.
S_A_V [24]

Answer:

\Delta \:H_{vap}=23.3054\ kJ/mol

Explanation:

The expression for Clausius-Clapeyron Equation is shown below as:

\ln P = \dfrac{-\Delta{H_{vap}}}{RT} + c

Where,  

P is the vapor pressure

ΔHvap  is the Enthalpy of Vaporization

R is the gas constant (8.314×10⁻³ kJ /mol K)

c is the constant.

For two situations and phases, the equation becomes:

\ln \left( \dfrac{P_1}{P_2} \right) = \dfrac{\Delta H_{vap}}{R} \left( \dfrac{1}{T_2}- \dfrac{1}{T_1} \right)

Given:

P_1 = 234.2 mmHg

P_2 = 522.6 mmHg

T_1 = 217.9 K

T_2 = 232.4 K

So,  

\ln \:\left(\:\frac{234.2\ mmHg}{522.6\ mmHg}\right)\:=\:\frac{\Delta \:H_{vap}}{8.314\times 10^{-3}\ kJ /mol K}\:\left(\:\frac{1}{232.4\ K}-\:\frac{1}{217.9\ K}\:\right)

\Delta \:H_{vap}=\frac{\left\{\ln \left(\:\frac{234.2}{522.6}\right)\:\times \:8.314\times 10^{-3}\right\}}{\left(\:\frac{1}{232.4}-\:\frac{1}{217.9}\:\right)}\ kJ/mol

\Delta \:H_{vap}=-\frac{10^{-3}\times \:8.314\ln \left(\frac{234.2}{522.6}\right)}{\frac{14.5}{50639.96}}\ kJ/mol

\Delta \:H_{vap}=-\frac{421020.62744\ln \left(\frac{234.2}{522.6}\right)}{14500}\ kJ/mol

\Delta \:H_{vap}=23.3054\ kJ/mol

7 0
3 years ago
It takes 163./kjmol to break an nitrogen-nitrogen single bond. calculate the maximum wavelength of light for which an nitrogen-n
jeyben [28]

Answer is:  the maximum wavelength of light is 7.34 × 10⁻⁷ m.

E= 163 kJ/mol; bond energy of one mole of nitrogen.

E = 163000 J/mol ÷ 6.022·10²³ 1/mol.

E = 2.707·10⁻¹⁹ J; bond energy per molecule.

E = h·c/λ.

c = 3.00 × 10⁸ m/s; light speed.

h = 6.62607004·10⁻³⁴ J·s; Planck constant.

λ(photon) = h·c/E.

λ(photon) = 6.62607004·10⁻³⁴ J·s · 3.00 × 10⁸ m/s ÷ 2.707·10⁻¹⁹ J.

λ(photon) = 7.34 × 10⁻⁷ m.

λ(photon) = 734 nm.

4 0
4 years ago
When a warm air mass and a cold air mass meet, but they push at each other and neither one can move, it is called a/an
Sergio039 [100]
When a warm air mass and a cold air mass meet and cant move its called "stationary front"
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4 years ago
How will you process the information in the table and on the map to
alexdok [17]

Answer:

By measuring through scale

Explanation:

CAN YOU TELL THE NAME OF COUNTRY BECAUSE I AM FROM NEPAL

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3 years ago
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