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4 years ago

How often does the earth revolve around the sun?

Physics

1 answer:

vodka [1.7K]4 years ago

3 0

Ok so basicly the earth goes around the sun every year and vis versa the sun goes aournd the earth every 24 hours.

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Jesse watches the Moon rise around 6:00 PM. When will the Moon most likely set?

Dominik [7]

On the average throughout a month, the moon appears to move
through the sky with a period of about 24 hours 48 minutes.

So if Jesse sees the Moon rise around 6:00 PM, he will see it
set the next morning if he is awake around 6:24 AM, and rise
again the next evening around 6:48 PM.

5 0

3 years ago

Read 2 more answers

A physics teacher performed a demonstration for a science class by pulling a crate across the floor

nika2105 [10]

Answer:

An opposing force caused by friction produced a lower acceleration than calculated.

Explanation:

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3 years ago

Pitch, roll, and yaw are all terms for specific kinds of motion. What does pitch mean?\

ad-work [718]

All these terms are related to an aircraft system. A pitch is a rotational motion around the side-to-side axis. It is a phenomenon when a plane is tilted upwards to increase lift of the tail or tilted downwards to decrease it. It is controlled by an elevator from the pilot maneuvering system.

8 0

3 years ago

1. An electron in an atom absorbs a photon with an energy of 2.38 eV and jumps from the n = 2 to n = 4 energy level in the atom.

oksian1 [2.3K]

1. $1.0\cdot 10^{-6}m$

First of all, let's convert the energy of the absorbed photon into Joules:

$E=2.38 eV \cdot (1.6\cdot 10^{-19}J/eV)=1.98\cdot 10^{-19} J$

The energy of the photon can be rewritten as:

$E=\frac{hc}{\lambda}$

where

h is the Planck constant

c is the speed of light

$\lambda$ is the wavelength of the photon

Re-arranging the formula, we can solve to find the wavelength of the absorbed photon:

$\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{1.98\cdot 10^{-19} J}=1.0\cdot 10^{-6}m$

2. 1.24 eV

In this case, when the electron jumps from the n=4 level to the n=3 level, emits a photon with wavelength

$\lambda=1.66\cdot 10^{-6}m$

So the energy of the emitted photon is given by the formula used previously:

$E=\frac{hc}{\lambda}$

and using

$\lambda=1.66\cdot 10^{-6}m$

we find

$E=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{1.0\cdot 10^{-6}m}=1.99\cdot 10^{-19}J$

converting into electronvolts,

$E=\frac{1.99\cdot 10^{-19} J}{1.6\cdot 10^{-19} J/eV}=1.24eV$

EDIT: an issue in Brainly does not allow me to add the last 2 parts of the solution - I have added them as an attachment to this post, check the figure in attachment.

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3 years ago

Connie teaches her children to call adults "sir" and "ma'am" and to say "please" and "thank you." These rituals are known as

Nat2105 [25]

Manners. they are known as manners.

5 0

3 years ago