The voltage in the extension cord is 30 V.
The problem above can be solved using ohm's law
⇒ Formula:
V = IR.................. Equation 1
⇒ Where:
- V = Voltage in the extension cord
- I = Current flowing through the extension cord
- R = Resistance of the extension cord.
From the question, I think there was a slight error in the value of the current given it suppose to be 500 A, and not 5.00 A
⇒ Given:
⇒ Substitute these values into equation 1
Hence the voltage in the extension cord is 30 V
Learn more about voltage here: brainly.com/question/4429782
The magnitude of the current in wire 3 is (I₃)= 0.33A
<h3>How to calculate the value of the magnitude of the current in wire 3 ?</h3>
To calculate the magnitude of the current in wire 3 we are using the Kirchhoff’s current law,
I₁ + I₂ + I₃ = 0
Where we are given,
I₁ = current in wire 1
=0.40 A.
I₂ = current in wire 2
= -0.73 A.
We have to calculate the magnitude of the current in wire 3, I₃
Now we put the known values in above equation, we get,
I₁ + I₂ + I₃ = 0
Or, I₃ = -.(I₁ + I₂)
Or, I₃ = -.(0.40 - 0.73)
Or, I₃ = 0.33 A
From the above calculation, we can conclude that the current in wire 3 is I₃ = 0.33 A
Learn more about current:
brainly.com/question/25537936
#SPJ4
You could use the formula
W=Fd
F(force)=20N
D(distance/displacement) =15m
W=(20N)(15m)
W= 300 J
1.u are given your formula as P=j over s
so ;1.2000 j over I = 2000w
2.5000j over 5s = 1000w
3.1,300j over 13s =100w
I aint so sure but u can take a shot..and please inbox me for futher details
From my research, the question has the following choices:
a.the lowest frequency at which a standing wave is possible
b. the highest frequency at which s standing wave is possiblec. the only frequency at which a standing wave is possible
d. the only frequency at which standing wave is not possible
From there, the correct answer is A.
