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nikdorinn [45]
3 years ago
10

The body uses _____ to control reactions within cells

Chemistry
2 answers:
sashaice [31]3 years ago
6 0
The answer is D.

The body uses enzymes to control reactions within the cells.
yKpoI14uk [10]3 years ago
5 0

Answer:

D. enzymes

Explanation:

Enzymes are catalysts that speed up the rate of a chemical reaction in the cell. Enzymes work by lowering the activation energy required by the reactant to get converted into products. Enzymes bind to substrates according to the lock and key model, each enzyme has a specific substrate to which it binds. For example, in the citric acid cycle  isocitrate requires the enzyme isocitrate dehydrogenase to get converted to alpha-ketoglutarate. The activity of an enzyme can be stopped by using inhibitors. Genetic mutation in an enzyme can cause metabolic disorder.

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An element with 7 electrons and 8 neutrons has an atomic mass of?? <br> 7, 8, or 15??
Alik [6]

Answer: 15

Explanation:

To find the atomic mass, you add the number of protons and neutrons. The number of electrons is the same as the number of protons

8 0
3 years ago
A student wants to measure the entropy of ice. What should the student do?
Helen [10]

Answer: Option (c) is the correct answer.

Explanation:

Entropy is defined as the degree of randomness. This means that more is the number of collisions taking place between atoms of a substance more will be the randomness.

Therefore, more will be the entropy of substance. We cannot measure the entropy but we can measure the change in entropy of a substance.

A thermometer is a glass tube that contains a liquid column generally mercury, and it is usually used to measure the temperature of human body.

A calorimeter is a device or apparatus that is used in a chemical reaction to measure the amount of heat involved.

Therefore, we can conclude that the student can't measure entropy directly, only an entropy change.

 

6 0
3 years ago
A 8.249 gram sample of copper is heated in the presence of excess fluorine. A metal fluoride is formed with a mass of 13.18 g. D
levacccp [35]

Answer:

CuF_2 the empirical formula of the metal fluoride.

Explanation:

Mass of copper heated = 8.249 g

Mass of copper fluoride formed = 13.18 g

Mass of fluorine gas in copper fluoride = x

13.18 g = 8.249 g + x\\x= 13.18 - 8.249 g = 4.931 g

Moles of copper :

= \frac{8.249 g}{63.546 g/mol}=0.1298 mol

Moles of fluorine:

= \frac{4.931 g}{18.998 g/mol}=0.2596 mol

For the empirical formula divide the smallest mole of an element with all the moles of elements present in the compound.

Copper= \frac{0.1298 mol}{0.1298 mol}=1\\Fluorine = \frac{0.2596 mol}{0.1298 mol}=2

The empirical formula of the copper fluoride = CuF_2

CuF_2 the empirical formula of the metal fluoride.

6 0
3 years ago
The Reaction
Effectus [21]

Answer:

Explanation:

From the information given:

We can say that the rate of reaction is utilized to decide the reaction speed, and it is subject to the rate constant.

The power of concentration related to the rate equation can be said to be the order of the reaction.

For zero-order reaction: it is the reaction whose rate is free and not dependent on the reactant's concentration.  

Concentration-time reaction is given as;

\mathbf{[A] = [A_o] -kt ---- (1)}

where;

t = time

k = rate constant

A_o = initial concentration of reactant

Thus, the plot between [A] and t needs to be a straight line.

On the other hand, The First order reaction is the reaction whose rate is straightforwardly corresponding to the reactant's concentration.  

Its concentration-time relation can be expressed as,

\mathbf{In([A])= In ([A_o])-kt   ---- (2)}

t = time

k = rate constant

[A_o] = initial concentration of the reactant

Then, the plot between [A] & t requires to be a straight line.

Presently, the plot between ln([A]) vs time appears to be in a straight line with the slope of the line equivalents to the rate constant (k).

hence,

slope = -k

Then;

\mathbf{k = -slope  ---- (3)}

Now; to discover the activation energy we need to utilize Arrhenius relation which is given as,

\mathbf{In(k) = In(K_o) - \dfrac{E_o}{RT}  ---- (4)}

From the above equation;

k_o = arrhenius parameter

Ea = activation energy

R = 8.314 J/mol.K

T = temperature in Kelvin

From the data given  for concentration vs time;

t[min]      Ca(mol/L)

0                      2

5                     1.6

9                     1.35

15                   1.1

22                    0.87

30                    0.7

40                    0.53

60                    0.35

a)

Since we can deduce the order of the reaction,

Let's assume that it is a zero-order reaction, Thus, the plot of Ca vs t can be seen in the first image attached below;

From the diagram, it is clear and obvious that it is NOT a straight line.

Thus, we conclude that this order is NOT a zero-order.

However, let also assume that order is first order,

Now, from the second diagram showing the plot of ln(Ca) vs t, we can deduce that it is a straight line which implies that it is the order of the reaction is first order.

Therefore, the equation for the first order is given as;

\mathbf{In([A]) = In ([A_o])- kt}

Recall that: the slope of the ln(A) v/s time will result in a rate constant,

Thus, from the graph we have;

slope = -0.0289 mol/L.min and:

slope = - k

Hence;

rate constant = k = 0.0289 mol/L.min and the order = 1st order

b)

On the off chance that we need to take more data points, we will like to take the data point in the scope of 40 min to 60 min time interval, on the grounds that the significant deviation is seen there. more information focuses will imply more accuracy.

8 0
3 years ago
Yes or no: will a precipitate form when solutions of ba(no3)2 and koh are mixed?
lakkis [162]
No, a precipitate will not form when barium nitrate, Ba(NO3)2, reacts with potassium hydroxide, KOH, in aqueous solution because both products are soluble in water.
3 0
3 years ago
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