Answer:
2. A resistor
3. Transistor
Sorry about before, go the answers now!
manganese The metal that is used as a sacrificial electrode to prevent the rusting of iron is manganese.
Answer:
The order is: electron, carbon, water, glucose, glycogen.
Explanation:
The electron is a negatively charged subatomic particle and is therefore the smallest.
Carbon is a chemical element, which belongs to the group-14 of periodic table and has atomic number 6.
Water is a odorless, almost colorless and tasteless chemical compound which is necessary for all the known living form. The chemical formula is H2O and it is composed of 2 hydrogen atoms and one oxygen atom.
Glucose is a monosaccharide sugar and a type of simple carbohydrate. The chemical formula is C6H12O6 and is composed of 6 carbon atoms, 6 oxygen atoms and 12 hydrogen atoms.
Glycogen is a branched polysaccharide molecule, which is composed of multiple monomeric glucose units. Therefore, it is the largest.
<u>Therefore, the increasing order is: electron, carbon, water, glucose, glycogen.</u>
Answer:
S = 7.9 × 10⁻⁵ M
S' = 2.6 × 10⁻⁷ M
Explanation:
To calculate the solubility of CuBr in pure water (S) we will use an ICE Chart. We identify 3 stages (Initial-Change-Equilibrium) and complete each row with the concentration or change in concentration. Let's consider the solution of CuBr.
CuBr(s) ⇄ Cu⁺(aq) + Br⁻(aq)
I 0 0
C +S +S
E S S
The solubility product (Ksp) is:
Ksp = 6.27 × 10⁻⁹ = [Cu⁺].[Br⁻] = S²
S = 7.9 × 10⁻⁵ M
<u>Solubility in 0.0120 M CoBr₂ (S')</u>
First, we will consider the ionization of CoBr₂, a strong electrolyte.
CoBr₂(aq) → Co²⁺(aq) + 2 Br⁻(aq)
1 mole of CoBr₂ produces 2 moles of Br⁻. Then, the concentration of Br⁻ will be 2 × 0.0120 M = 0.0240 M.
Then,
CuBr(s) ⇄ Cu⁺(aq) + Br⁻(aq)
I 0 0.0240
C +S' +S'
E S' 0.0240 + S'
Ksp = 6.27 × 10⁻⁹ = [Cu⁺].[Br⁻] = S' . (0.0240 + S')
In the term (0.0240 + S'), S' is very small so we can neglect it to simplify the calculations.
S' = 2.6 × 10⁻⁷ M
