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UkoKoshka [18]
3 years ago
13

What is the lead concentration of a saturated solution of lead(II) sulfate containing 0.020 M Na2SO4? Ksp for PbSO4 = 6.3x10-7.

Chemistry
1 answer:
labwork [276]3 years ago
8 0

Answer:

i want to help but  i   d   k. the answer :( sorry i couldnt help

Explanation:

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You have three drinks in front of you. you know how they are made, but are unsure which one has the highest concentration of jui
GuDViN [60]

(I think) you would have to divided the number i dont know the exact answer but ya hope this help
4 0
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61.0 mol of P4O10 contains how many moles of P
galina1969 [7]
61mol * 4 = 244moles of P
5 0
3 years ago
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I need help with these 4
storchak [24]

Rift Valley Examples

  • East African
  • Rhine Rift Valley (Germany)
  • Baikal Rift Valley (Russia)

Rift Valley Facts/Characteristics

  • Bordered by fault zones and separating land masses
  • A portion of land that drops, forming a valley.
  • Formed as tectonic plates move.

Fossils - Examples

  • Bones
  • Shells
  • Exoskeletons
  • Stone imprints of animals.

Non Examples of Fossils

  • Stones
  • rocks
  • Some bones (If they are fossils they will be a lot heavier than other bones.

Hope this helps.

5 0
3 years ago
Many portable gas heaters and grills use propane, C3H8(g). Using enthalpies of formation, calculate the quantity of heat produce
Elodia [21]

Answer:  600 kJ

-

Explanation:

                        C₃H₈ (g)  + 5 O₂ (g) =============== 3 CO₂ (g)  +  4 H₂O (l)

Δ⁰Hf   kJ/mol       -104             0                                       -393.5         -285.8

Δ⁰Hcomb C₃H₈ = 3(-393.5) + 4 (-285.80) - (-104)  kJ/mol

Δ⁰Hcomb = 2219.70 kJ/mol

n= m /MW   MW c₃H₈ = 44.1 g/mol

n= 12 g/44.1 g/mol = 0.27 mol

then for 12 g the heat released will be

0.27 mol x 2219.70 kJ/mol =  600 KJ

4 0
3 years ago
Read 2 more answers
Given 6193 mL of a gas at 62.3 °C. What is its volume at 38.1 °C?
Luden [163]

Answer:

5746.0 mL.

Explanation:

We can use the general law of ideal gas:<em> PV = nRT.</em>

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and P are constant, and have two different values of V and T:

<em>V₁T₂ = V₂T₁</em>

<em></em>

V₁ = 6193.0 mL, T₁ = 62.3°C + 273 = 335.3 K.

V₂ = ??? mL, T₂ = 38.1°C + 273 = 311.1 K.

<em>∴ V₂ = V₁T₂/T₁ </em>= (6193.0 mL)(311.1 K)/(335.3 K) = <em>5746.0 mL.</em>

5 0
3 years ago
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