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saul85 [17]
3 years ago
13

The compound before the arrow are called blank and the compound after the arrow are called blank

Chemistry
1 answer:
Norma-Jean [14]3 years ago
8 0
First one is reactants and then second one is products
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4. When a turbine spins, it generates electrical energy and that is where it gets its name from.
Elena L [17]
If it’s hydraulic turbine then it’s potential and kinetic energy and if it’s a thermal process then heat energy from the fuel burnt runs the turbine
8 0
2 years ago
In a chemical interaction 10 g of hydrogen chloride is added to 20 g of zinc to form 24 g of zinc chloride and a certain amount
marin [14]

The Answer would be...

A. 6g

I hope this is right!

6 0
3 years ago
Read 2 more answers
Benzene is a starting material in the synthesis of nylon fibers and polystyrene (styrofoam). Its specific heat capacity is 1.74
Leona [35]

Answer:

D

Explanation:

The amount of energy released or absorbed is equal the product of the mass, the specific heat capacity and the temperature change. The temperature change being the difference between the final and initial temperature.

Q = mc∆T

Q = heat energy (Joules, J) m = mass of a substance (kg) c = specific heat (units J/g∙K)

∆ is a symbol meaning "the change in" ∆T = change in temperature (Kelvins, K)

From the data provided in the question, we can deduce that:

Q = 16.7KJ = 16,700J

m = 225g

c = 1.74J/g.k

For the temperature, let the final temperature be f. This means our ∆T = f - 20

16,700 = 225 * 1.74 * (f - 20)

16700 = 391.5 (f - 20)

f - 20 = 16700/391.5

f - 20 = 42.7

f = 20 + 42.7 = 62.7

5 0
3 years ago
The specific heat of copper is 0.093 cal/g0C. Calculate the temperature change that occurs if 28 g of copper at 25 0C absorbs 58
Umnica [9.8K]

Answer:

22.27 °C = ΔT

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m × c × ΔT

Given data:

mass = 28 g

heat absorbed = 58 cal

specific heat of copper =  0.093 cal/g .°C

temperature change =ΔT= ?

Solution:

Q = m × c × ΔT

58 cal = 28 g × 0.093 cal /g.°C × ΔT

58 cal = 2.604 cal.°C × ΔT

58 cal / 2.604 cal .°C = ΔT

22.27 °C = ΔT

5 0
3 years ago
How does peer review affect research?
Mice21 [21]

Answer:

I am pretty sure the answer is C.

Explanation:

4 0
2 years ago
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