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3 years ago

What would most likely happen if the moon was closer to Earth (take tides into consideration)?

Chemistry

2 answers:

Gekata [30.6K]3 years ago

3 0

Answer:

Low tides would be lower and high tides would be higher and any low lying coastline would be flooded

Explanation:

Also...

If the moon got about 20 times closer it would make a gravitational force 400 times greater than what we are used to now

laiz [17]3 years ago

3 0

The tides wold be more extreme

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Predict the products of the reaction below. That is, complete the right-hand side of the chemical equation. Be sure your equatio

Furkat [3]

Answer:

HNO₃ (aq) —> H⁺ (aq) + NO₃¯ (aq)

Explanation:

From the question given above

HNO₃ + H₂O —> ?

Nitric acid, HNO₃ reacts with water, H₂O to form aqueous solution of nitric acid as illustrated below:

HNO₃ + H₂O —> HNO₃ (aq)

Nitric acid is a strong acid and, so will ionised completely when dissolved in water. This is illustrated below:

HNO₃ (aq) —> H⁺ (aq) + NO₃¯ (aq)

6 0

3 years ago

How many moles of carbon, hydrogen, and oxygen are present in a 100-g sample of ascorbic acid?

Y_Kistochka [10]

There are:

3.41 moles of C

4.54 moles of H

3.40 moles of O.

Why?

To solve the problem, the first thing that we need to do is to write the chemical formula of the ascorbic acid.

$C_{6}H_{8}O_{6}$

Now, we know that there are 100 grams of the compound, so, the masses of each element will represent the percent in the compound.

We have that:

$C_{6}=12.0107g*6=72.08g\\\\H_{8}=1.008g*8=8.064g\\\\O_{6}=15.999g*6=95.994g\\\\C_{6}H_{8}O_{6}=72.08g+8.064g+95.994g=176.138g$

To know the percent of each element, we need to to the following:

$C=\frac{72.08g}{176.138g}*100=0.409*100=40.92(percent)\\\\H=\frac{8.064g}{176.138g}*100=4.58(percent)\\\\O=\frac{95.994}{176.138g}*100=54.49(percent)$

So, we know that for the 100 grams of the compound, there are:

40.92 grams of C

4.58 grams of H

54.49 grams of O

We know the molecular masses of each element:

$C=12.0107\frac{g}{mol}\\\\H=1.008\frac{g}{mol}\\\\O=15.999\frac{g}{mol}{mol}$

Now, to calculate the number of moles of each element, we need to divide the mass of each element by the molecular mass of each element:

$C=\frac{40.92g}{12.010\frac{g}{mol}}=3.41mol\\\\H=\frac{4.58g}{1.008\frac{g}{mol}}=4.54mol\\\\O=\frac{54.49g}{15.999\frac{g}{mol}}=3.40mol$

Hence, we have that there are 3.41 moles of C, 4.54 moles of H, and 3.40 moles of O.

Have a nice day!

5 0

3 years ago

Someone pls help me With this I will make you as brain

RoseWind [281]

The answer to that question is c

5 0

2 years ago

Briefly discuss interpretations of your observations and results. Discuss how your observations illustrated LeChatelier's princi

Dvinal [7]

Answer:

Le Chatelier's principle can be applied in explaining the results

Explanation:

According to Le Chatelier's principle, when a constraint such as a change in concentration in this case is imposed on a chemical system in equilibrium, the system will adjust itself in such a way as to annul the constraint imposed.

Hence, when the color of the solution was more like that of the control, the reaction would shift towards the left. Similarly, when the color was more like it was towards the reactant, the reaction would shift towards the right.

If we were to prepare calcium oxalate, we should prepare it in a base solution. This is because when the base was added to calcium oxalate, it did not form any precipitate but when an acid was added to the calcium oxalate, it formed a precipitate.

4 0

2 years ago

Part D

qwelly [4]

Answer:

Explanation:

The number on the top right of the symbol shows ATOMIC NUMBER , if it is written alone only one digit or number overall .

And if the number is also in bottom left then bottom left number will be ATOMIC NUMBER and top right will be MASS NUMBER

Hope this will help you *-*

7 0

3 years ago