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3 years ago

3. 2 HCl (aq)

Chemistry

1 answer:

tekilochka [14]3 years ago

6 0

Explanation:

balance the equation ...HCl,Ba(OH) and BaCl2 are aqueous

know groups of the elements H 1+ ,Cl -,Ba 2+,OH-

write complete ionic eqution and eliminate spectator ions those appearing on both sides Cl and Ba

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A gas has a pressure of 1.34 atm when the temperature is 237K. The gas is then heated until the temperature measures 312K. What

alexandr1967 [171]

The answer for the following question is answered below.

Therefore the new pressure of the gas is 1.76 atm.

Explanation:

Given:

Initial pressure of the gas = 1.34 atm

Initial temperature of the gas = 273 K

final temperature of the gas = 312 K

To solve:

Final temperature of the gas

We know;

From the ideal gas equation

P × V = n × R × T

So;

from the above equation we can say that

P ∝ T

$\frac{P}{T}$ = constant

$\frac{P_{1} }{P_{2} }$ = $\frac{T_{1} }{T_{2} }$

Where;

$P_{1}$ = initial pressure of a gas

$P_{2}$ = final pressure of a gas

$T_{1}$ = initial temperature of a gas

$T_{2}$ = final temperature of a gas

$P_{2}$ = $\frac{1.34*312}{237}$

$P_{2}$ = 1.76 atm

Therefore the new pressure of the gas is 1.76 atm.

6 0

3 years ago

Most genetic mutations are repaired by____

Kay [80]

The correct Anwser is enzymes

7 0

3 years ago

Gaseous hydrogen and oxygen can be prepared in the laboratory from the decomposition of gaseous water. The equation for the reac

monitta

Answer:

75.5 g O₂ (g) can be produced from 42.6 g of H₂O (g)

Explanation:

1) Balanced chemical equation (given):

2H₂O(g) → 2H₂(g) + O₂(g)

2) Mole ratios:

2 moles H₂O(g) : 2 moles H₂(g) : 2 moles O₂(g)

3) Calculate the number of moles of reactant (H₂0):

number of moles = mass in grams / molar mass

molar mass of water: 18.015 g/mol

mass in grams of water: 42.6 g

number of moles = 42.6 g / 18.05 g/mol = 2.36 moles H₂O

4) Set a proportion using the mole ratio O₂ to H₂O and the actual number of moles of H₂O:

2 moles O₂ / 2 moles H₂O = x / 2.36 moles H₂O

x = 2.36 moles O₂

5) Convert 2.36 moles O₂ to grams:

mass in grams = number of moles × molar mass

mass = 2.36 moles × 32.00 g/mol = 75.5 g O₂

4 0

3 years ago

Read 2 more answers

Given the following: [G3P] = 1.5x10-5M; [BPG] = 3.0x10-3M ; [NAD+] = 1.2x10-5M; [NADH]=1.0x10-4 ; [HPO42-]= 1.2x10-5 M; pH = 7.5

mel-nik [20]

Answer: The given reaction is non-spontaneous in nature.

Explanation:

To calculate the $H^+$ concentration, we use the equation:

$pH=-\log[H^+]$

We are given:

pH of the solution = 7.5

$7.5=-\log [H^+]$

$[H^+]=10^{-7.5)=3.1\times 10^{-8}M$

For the given chemical equation:

$\text{Glyceraldehyde3-phosphate }+NAD^++HPO_4^{2-}\rightarrow \text{1,3-Biphosphoglycerate }+NADH+H^+$

The equation used to Gibbs free energy of the reaction follows:

$\Delta G=\Delta G^o+RT\ln K_{eq}$

where,

$\Delta G$ = free energy of the reaction

$\Delta G^o$ = standard Gibbs free energy = 6.3 kJ/mol = 6300 J/mol (Conversion factor: 1kJ = 1000J)

R = Gas constant = 8.314J/K mol

T = Temperature = $25^oC=[273+25]K=298K$

$K_{eq}$ = Ratio of concentration of products and reactants = $\frac{[BPG][NaDH][H^+]}{[G_3P][NAD^+][HPO_4^{2-}]}$

$[BPG]=3.0\times 10^{-3}M$

$[NADH]=1.0\times 10^{-4}M$

$[H^+]=3.1\times 10^{-8}M$

$[G_3P]=1.5\times 10^{-5}M$

$[NAD^+]=1.2\times 10^{-5}M$

$[HPO_4^{2-}]=1.2\times 10^{-5}M$

Putting values in above equation, we get:

$\Delta G=6300J/mol+(8.314J/K.mol\times 298K\times \ln (\frac{(3.0\times 10^{-3})\times (1.0\times 10^{-4})\times (3.1\times 10^{-8})}{(1.5\times 10^{-5})\times (1.2\times 10^{-5})\times (1.2\times 10^{-5})}))\\\\\Delta G=9917.02J/mol=9.92kJ/mol$

For the reaction to be spontaneous, the Gibbs free energy of the reaction must come out to be negative.

As, the Gibbs free energy of the reaction is positive. The reaction is said to be non-spontaneous.

Hence, the given reaction is non-spontaneous in nature.

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3 years ago

8.Based on Kepler’s work, which best describes the orbit of a planet around the Sun?

Zepler [3.9K]

the answer is C. 1.26 days

4 0

3 years ago

Read 2 more answers