Question

A Net Force of 9.0 N acts through a distance of 3.0 m in a time of 3.0 s. The work done is?

Answer 1

Work done is the distance a force acts over.

So, the work done here is 9.0N * 3.0m = 27 J

Answer 2

Answer:

work done would be 27 J

Explanation:

Work done is the product of force and displacement in the direction of force

So here we know that

Applied force = 9.0 N

displacement = 3.0 m

now as per formula of work done we know that

W = (Force)(displacement)

now plug in all values in it

$W = (9.0 N) \times (3.0 m)$

$W = 27 J$

So work done would be 27 J