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3 years ago

A Net Force of 9.0 N acts through a distance of 3.0 m in a time of 3.0 s. The work done is?

Physics

2 answers:

JulijaS [17]3 years ago

5 0

Work done is the distance a force acts over.

So, the work done here is 9.0N * 3.0m = 27 J

Reptile [31]3 years ago

5 0

Answer:

work done would be 27 J

Explanation:

Work done is the product of force and displacement in the direction of force

So here we know that

Applied force = 9.0 N

displacement = 3.0 m

now as per formula of work done we know that

W = (Force)(displacement)

now plug in all values in it

$W = (9.0 N) \times (3.0 m)$

$W = 27 J$

So work done would be 27 J

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2 years ago

In your physics lab you are given a 10.1-kg uniform rectangular plate with edge lengths 68.7 cm by 47.5 cm. Your lab instructor

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Answer:

2.35 kgm^2

Explanation:

we take length 68.7 cm as x-axis and 47.5 cm as y-axis then the axis about which we have to find out moment of inertia will be z-axis.

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3 years ago

A 75.0-kg person climbs stairs, gaining 2.50 m in height. Find the work done to accomplish this task.

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Answer:

$W=1837.5J$

Explanation:

A force exerts work when there is a displacement of its point of application in the direction of that force. Therefore, the work done by a system is defined as the inner product between the applied force and the displacement:

$W=\vec{F}\cdot \vec{d}\\W=Fcos\theta d$

In this case, we have:

$F=mg\\h=dcos\theta$

So, replacing this:

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4 years ago

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Answer:

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Explanation:

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wavelength, λ = c / f = (3 x 10^8) / (1100000) = 272.73 m

Thus, the wavelength is 272.73 m.

(b) at t = 3.1 microsecond = 3.1 x 10^-6 s

E = Eo Sin (2 π ft)

E = 0.62 Sin (2 x 3.14 x 1100 x 10^3 x 3.1 x 10^-6)

E = 0.62 Sin (21.4148)

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