A Net Force of 9.0 N acts through a distance of 3.0 m in a time of 3.0 s. The work done is?
2 answers:
Answer:
work done would be 27 J
Explanation:
Work done is the product of force and displacement in the direction of force
So here we know that
Applied force = 9.0 N
displacement = 3.0 m
now as per formula of work done we know that
W = (Force)(displacement)
now plug in all values in it
So work done would be 27 J
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Note: if the professor wants the distance between the m = 0 and m = 1 maxima to be 25 cm
Answer:
d = 1.0128×10⁻⁵m
Explanation:
given:
length L = 4.0m
maximum distance between m = 0 and m = 1 , y = 25cm = 0.25m
wavelength λ = 633nm = 633×10⁻⁹m
note:
dsinθ = mλ (constructive interference)
where d is slit seperation, θ is angle of seperation , m is order of interference , and λ is wavelength
for small angle
sinθ ≈ tanθ
mλ
d = 1.0128×10⁻⁵m