Answer:
W = 0.060 J
v_2 = 0.18 m/s
Explanation:
solution:
for the spring:
W = 1/2*k*x_1^2 - 1/2*k*x_2^2
x_1 = -0.025 m and x_2 = 0
W = 1/2*k*x_1^2 = 1/2*(250 N/m)(-0.028m)^2
W = 0.060 J
the work-energy theorem,
W_tot = K_2 - K_1 = ΔK
with K = 1/2*m*v^2
v_2 = √2*W/m
v_2 = 0.18 m/s
Given the time, the final velocity and the acceleration, we can calculate the initial velocity using the kinematic equation A:

A skateboarder flies horizontally off a cement planter. After a time of 3 seconds (Δt), he lands with a final velocity (v) of −4.5 m/s. Assuming the acceleration is -9.8 m/s² (a), we can calculate the initial velocity of the skateboarder (v₀) using the kinematic equation A.

Given the time, the final velocity and the acceleration, we can calculate the initial velocity using the kinematic equation A:

Learn more: brainly.com/question/4434106
Answer:
175J
Explanation:
Work done is given by the product of the force applied and the distance travelled as a result of that force.
Or in formula , W=F×d
Thus,
W= 35 × 5.0=175 J or 1.8 e2 J
In order for the object to move upward, it needs an upward force
that's at least equal to its own weight.
Weight = (mass) x (gravity) = (35 kg) x (9.8 m/s²) = 343 N.
The engine thrust has to be more than 343 N.