The force of the tripped catch exerted on the 2.5 Kg ball moving at 8.5 m/s to the Left is 160 N
<h3>Data obtained from the question </h3>
- Initial velocity (u) = 8.5 m/s
- Final velocity (v) = 7.5 m/s
- Time (t) = 5 ms = 0.25 s
- Mass (m) = 2.5 Kg
- Force (F) = ?
<h3>How to determine the force</h3>
The force exerted on the ball can be obtained as follow:
F = m(v + u) / t
F = [2.5(7.5 + 8.5)]/ 0.25
F = 40 / 0.25
F = 160 N
Thus, the force exerted on the ball is 160 N
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Answer: Not 100% sure but I believe the answer is B.
Hope this helps! ^^
Well 200 doubled or (x2)=400 if that’s what it means
The visible spectrum of the electromagnetic spectrum is made up of "<span>red, orange, yellow, green, blue, and violet light"
In short, Your Answer would be Option C
Hope this helps!</span>
Answer:
Net Charge is -1.6 x 10 (to the negative 19th power) C. l
Explanation: