Answer:
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Answer:
the magnitude of the force that one particle exerts on the other is 79.08 N
Explanation:
given information:
q₁ = 3.77 μC = -3.77 x 10⁻⁶ C
q₂ = 4.39 μC = 4.39 x 10⁻⁶ C
r = 4.34 cm = 4.34 x 10⁻² m
What is the magnitude of the force that one particle exerts on the other?
lFl = kq₁q₂/r²
= (9 x 10⁹) (3.77 x 10⁻⁶) (4.39 x 10⁻⁶)/(4.34 x 10⁻²)²
= 79.08 N
Sensible heat involves change in temperature of a substance. As the name suggests, it is the heat one can feel or sensed. When a system exchange sensible heat, its volume, pressure and state do not change. The sensible heat can be measured with the help of thermometer. The other type of heat is latent heat which involves change in state of the substance.
Explanation: Solution
1.
Gravitational potential energy
U=mgh=500*9.8*50
U=245000 J
2.
Kinetic energy is present at bottom of the hill
K=(1/2)mV2=(1/2)*500*27.82
K=193210 J
3.
Work done by friction
W=193210-245000=-51790 J
Answer: Yes
Explanation:
Given
Martin initial speed is 
Stones is at 170 m ahead
Deceleration 
Using the equation of motion 
Insert the values

So, it took 100 m to stop completely. Hence martin will be able to stop in time.