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Gekata [30.6K]
3 years ago
11

How long will it take Matthew to jog 321 m at 5.8m/s?

Physics
1 answer:
Xelga [282]3 years ago
8 0
Give the other person brainest I was gonna answer but found no need if you get me
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Science
Temka [501]
When a light wave encounters an object, they are either transmitted,reflected,absorbed,refracted,diffracted, or scattered depending on the wave
3 0
3 years ago
A cylindrical capacitor has an inner conductor of radius 2.7 mmmm and an outer conductor of radius 3.1 mmmm. The two conductors
Mars2501 [29]

Answer:

(A) Capacitance per unit length = 4.02 \times 10^{-10}

(B) The magnitude of charge on both conductor is Q = 4.22 \times 10^{-19} C and the sign of charge on inner conductor is +Q and the sign on outer conductor is -Q

Explanation:

Given :

Radius of inner part of conductor  (R_{1}) = 2.7 \times 10^{-3} m

Radius of outer part of conductor  (R_{2}) = 3.1 \times 10^{-3} m

The length of the capacitor (l) = 3 \times 10^{-3} m

(A)

Capacitance is purely geometrical property. It depends only on length, radius of conductor.

From the formula of cylindrical capacitor,      

     C = \frac{2\pi\epsilon_{o} l }{ln\frac{R_{2} }{R_{1} } }

Where, \epsilon_{o} = 8.85 \times 10^{-12}

But we need capacitance per unit length so,

     \frac{C}{l}  = \frac{2\pi\epsilon_{o}  }{ln\frac{R_{2} }{R_{1} } }

capacitance per unit length = \frac{6.28 \times 8.85 \times 10^{-12} }{ln(1.148)} = 4.02 \times 10^{-10}

(B)

The charge on both conductors is given by,

     Q = C \Delta V

Where, C = capacitance of cylindrical capacitor and value of C = 12.06 \times 10^{-13} F, \Delta V = 350 \times 10^{-3} V

∴ Q = 4.22 \times 10^{-19} C

The magnitude of charge on both conductor is same as above but the sign of charge is different.

Charge on inner conductor is +Q and Charge on outer conductor is -Q.

8 0
4 years ago
The wall is 500 sq. feet. A gallon of paint covers 160 sq. feet. What is an appropriate conversion factor to help determine how
lana66690 [7]

Answer:

Explanation:

Given

Wall is 500 ft^2 in area

160\ ft^2 requires 1 gallon of paint

so using unitary method

1\ ft^2 requires \frac{1}{160}   gallon of paint

500 ft^2 wall will require =500\times \frac{1}{160} gallons of paint

=3.0125\ gallons

   

4 0
3 years ago
An arrow is shot at an angle 38 ◦ with the horizontal. It has a velocity of 46 m/s. How high will the arrow go?
Klio2033 [76]

Answer:

40·919 m

Explanation:

Initial velocity of the arrow = 46 m/s

Angle at which it is thrown from horizontal = 38°

<h3>At the maximum height, the vertical component of velocity will be 0</h3>

Initial velocity in vertical direction = 46 × sin(38) = 28·32 m/s

From the formula

<h3>v² - u² = 2 × a × s</h3>

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

Considering the formula in vertical direction and taking upward direction as positive

v = 0

u = 28·32 m/s

a = - g = - 9·8 m/s²

Let s be the maximum height

- 28·32² = - 2 × 9.8 × s

⇒ s = 40·919 m

∴ The arrow will go 40·919 m high

8 0
3 years ago
PLSSS HELPPPPP!! due today @ 8:30!
romanna [79]

Answer:

(1) weight = 565N

distance = 325m

time= 12.6s

power = work done/time

work done= force * distance

= 565*3.25 =1836.25

:. power = 1836.25\12.6

=145.7!

(2) the books will add more to her weight and thereby increasing her power output.

4 0
3 years ago
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