"Voltage" is the "pressure" that makes electrons want to leave where they are
and head in some direction, if there's conducting material in that direction.
"Current" is the rate at which they all migrate in that direction.
Answer:
First, the different indices of refraction must be taken into account (in different media): for example, the refractive index of light in a vacuum is 1 (since vacuum = c). The value of the refractive index of the medium is a measure of its "optical density": Light spreads at maximum speed in a vacuum but slower in others transparent media; therefore in all of them n> 1. Examples of typical values of are those of air (1,0003), water (1.33), glass (1.46 - 1.66) or diamond (2.42).
The refractive index has a maximum value and a minimum value, which we can calculate the minimum value by means of the following explanation:
The limit or minimum angle, α lim, is defined as the angle of refraction from which the refracted ray disappears and all the light is reflected. As in the maximum value of angle of refraction, from which everything is reflected, is βmax = 90º, we can know the limit angle (the minimum angle that we would have to have to know the minimum index of refraction) by Snell's law:
βmax = 90º ⇒ n 1x sin α (lim) = n 2 ⇒ sin α lim = n 2 / n 1
Explanation:
When a light ray strikes the separation surface between two media different, the incident beam is divided into three: the most intense penetrates the second half forming the refracted ray, another is reflected on the surface and the third is breaks down into numerous weak beams emerging from the point of incidence in all directions, forming a set of stray light beams.
Answer: D.
Explanation: Orange, at 3 meters per second if you calculate the net force being applied to the system.
hope this helps! ✌
A is not the correct answer because the amplitude and oscillation and there is 1/2 A in oscillation
Answer:
0.75 m³/s
Explanation:
Applying,
Q = vA.................... Equation 1
Where Q = flow rate of the water, v = velocity of the water, A = area of the pipe.
From the question,
Given: v = 2.5 m/s, A = 0.3 m²
Substitute these values into equation 1
Q = 2.5(0.3)
Q = 0.75 m³/s
Hence the flow rate of water in the pipe is 0.75 m³/s
