Answer:
76.9690 square units (rounded off to four decimal values)
Step-by-step explanation:
The diameter of the semicircle is 14 units
The radius of the semicircle is thus 14 ÷ 2 = 7 units
Area of a semicircle is given by: 
× π × r²
In our case, the area is = × π × 7² = 76.9690200129 square units
Or 76.9690 square units (rounded off to four decimal values)
Similar triangles may or may not have congruent sides, but the ratio of the corresponding sides will always be congruent.
<u>(3) Corresponding sides of △MNP and △RST</u>
Given that △MNP ∼△RST.
This means that, the corresponding sides are:
- MN and RS
- MP and RT
- NP and ST
<u>(4) The equal measures</u>
Given that △ABC ∼△TUV
This means that, the corresponding angles are equal, but corresponding sides are not.
So, the equal measures are:
- (a). the measures of ∠A and ∠T
- (c). the ratios of the sides BC/UV and AC/TV
The unequal measure is:
- (b). the perimeters of the two triangles
<u>(c) Scale mapping</u>
The scale mapping is given as:
The above scale means that 1 inches on the scale represents 100 miles of the actual distance.
Take for instance, 5 inches would represent 500 miles.
500 is 5 times 100
Hence, the actual distance between two towns 100 times the map distance between the two towns
Read more about similar triangles at:
brainly.com/question/14285697
Use compound interest formula F=P(1+i)^n twice, one for each deposit and sum the two results.
For the P=$40,000 deposit,
i=10%/2=5% (semi-annual)
number of periods (6 months), n = 6*2 = 12
Future value (at end of year 6),
F = P(1+i)^n = 40,000(1+0.05)^12 = $71834.253
For the P=20000, deposited at the START of the fourth year, which is the same as the end of the third year.
i=5% (semi-annual
n=2*(6-3), n = 6
Future value (at end of year 6)
F=P(1+i)^n = 20000(1+0.05)^6 = 26801.913
Total amount after 6 years
= 71834.253 + 26801.913
=98636.17 (to the nearest cent.)
Answer:
1002
Step-by-step explanation:
171x6=1026
171×2=342
1026-342=684
684+318=1002
Answer:
7/25
Step-by-step explanation:
θ lies in quadrant ii
so 2θ lies in quadrant iv
csc θ=5/3
sin θ=3/5 (sin θ=1/csc θ)
[cos(α+β)=cosαcosβ-sinαsinβ]
cos (2θ)=cos(θ+θ)=cos θ cos θ-sin θ sin θ=cos² θ-sin ²θ=1-sin²θ-sin²θ=1-2sin²θ
=1-2 (3/5)²
=1-2(9/25)
=1-18/25
=(25-18)/25
=7/25
