Answer:
We have,
Initial volume is V
1
Initial temprature is T
1
=75
0
C
Initial pressure is P
1
So, final temprature is T
2
=273+75=348K
V
2
=V
1
−
100
15
V
1
=
100
85V
1
Applying the gas formula,
T
1
P
1
V
1
=
T
2
P
2
V
2
348
P
1
V
1
=
T
2
×100
2P
1
×85V
1
T
2
=
100
2×85×348
T
2
=591.6K
To find the molarity of the compound, simply determine the molar mass of MgCl2 and then convert 50 g to moles using the molar mass of the compound. Then convert 150 ml to L = 0.15 L
Then divide the moles amount by the volume in L.
