<u>We are given:</u>
Mass of the mixture = 1.5 grams
Number of Moles of NaHCO₃ = 0.01 mole
<u>Mass of 0.01 moles of NaHCO₃:</u>
Mass = number of moles * Molar mass
Mass = 0.01 * 84
Mass = 0.84 grams
<u>Mass% of Na in NaHCO₃:</u>
Molar mass of NaHCO₃ = 84 grams/mol
Molar mass of Na = 23 grams / mol
Mass% = (Molar mass of Na / Molar mass of NaHCO₃) * 100
Mass% = (23/84) * 100
Mass% = 27%
<u>Mass of Na in 0.01 moles:</u>
Since the Mass% of Na is 27% and the total mass is 0.84 grams
So, we can say that 27% of 0.84 is the mass of Na
Mass of Na = 0.84 * 0.27
Mass of Na = 0.23 grams
<u>Mass% of Na in the mixture:</u>
Total mass of the mixture = 1.5 grams
Mass of Na in the mixture = 0.23 grams
Mass% of of Na in the Mixture = (Mass of Na / Mass of Mixture) * 100
Mass% of Na = (0.23 / 1.5) * 100
Mass% of Na = 15.3%
Therefore, we have 15.3% Na in the given mixture by mass
