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AysviL [449]
2 years ago
14

Iodine (I2) and (Br2) react in a closed 2.0L container at 150°C to produce iodine monobromide (IBr), according to the following

equation:
I2(g) + Br2(g) <--> 2IBr(g).

The K value is 1.2 x 102.
What is the initial concentration of bromine
Chemistry
1 answer:
zaharov [31]2 years ago
8 0

Answer: 409

Explanation:

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A buffer contains equal amounts of a weak acid and its conjugate base and has a ph of 5.25. part a which would be a reasonable v
gregori [183]
Hello!

After the addition of a small amount of acid, a reasonable value of buffer pH would be 5,15.

If initially there are equal amounts of a weak acid and its conjugate base, the pH would be equal to the pKa, according to the Henderson-Hasselbach equation:

pH=pKa+log( \frac{[A^{-}] }{[HA]} ) \\ \\ if [A^{-}]=[HA] \\ \\ pH=pKa + log (1) \\ \\ pH=pKa + 0=5,25

So, when adding a little amount of acid the pH should be only a little lower than the pKa. The value from the list that is a little lower than the pKa is 5.15

Have a nice day!
7 0
3 years ago
Calculate the fraction of acetic acid that is in the dissociated form in his solution. Express your answer as a percentage. You
Sliva [168]

Answer:

0.11%

Explanation:

Without mincing words, let us dive straight into the solution to the question/problem. The first step to solve this question is to write out the chemical reaction, that is the reaction showing the dissociation of acetic acid.

CH3COOH <=======================================> CH3COO⁻ + H⁺

Initially, the amount present in the acetic acid which is = 12M, the concentration for CH3COO⁻  and H⁺ is 0 respectively.

At equilibrium, the amount present in the acetic acid which is = 12 - x, the concentration for CH3COO⁻ = x  and H⁺ = x respectively. Note that the ka for acetic acid = 1.8 × 10⁻⁵.

1.8 × 10⁻⁵ = x²/ 14 - x. Therefore, x = 0.0158 M.

The next thing to do is to calculate for the percentage of dissociation, this can be done as given below:

percentage of dissociation = x/14 × 100. Recall that the value that we got for x = 0.0158 M. Hence, the percentage of dissociation = 0.0158 M/ 14m × 100 = 0.11%

7 0
2 years ago
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