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AysviL [449]
3 years ago
14

Iodine (I2) and (Br2) react in a closed 2.0L container at 150°C to produce iodine monobromide (IBr), according to the following

equation:
I2(g) + Br2(g) <--> 2IBr(g).

The K value is 1.2 x 102.
What is the initial concentration of bromine
Chemistry
1 answer:
zaharov [31]3 years ago
8 0

Answer: 409

Explanation:

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Chemist and physicist marie curie became famous for her pioneering research on radioactivity. What are the two chemical elements
wolverine [178]

Answer:

The two elements are POLONIUM and RADIUM.

Explanation:

Maria Curie is a French physicist and chemist, though she was of a Polish naturals. She was the first woman to receive a Noble Price which she earned for conducting leading and head way research on radioactivity. She discovered the theory of radioactivity; also the techniques isolating radioactive isotopes. These helped her and her husband discover Polium and Radium.

4 0
3 years ago
Read 2 more answers
What are the errors in this table check all that apply
Marat540 [252]

Answer:

Cannot be determined

Explanation:

Hi there,

Could you please add an attachment of the table? We cannot tell what the errors are if there is no table.

4 0
2 years ago
Consider the following reaction between calcium oxide and carbon dioxide: CaO(s)+CO2(g)→CaCO3(s) A chemist allows 14.4 g of CaO
sweet-ann [11.9K]

Answer:

Theoretical yield =26.03 g

Percent yield = 87%

Limiting reactant = CaO

Explanation:

Given data:

Mass of CaO = 14.4 g

Mass of CO₂ = 13.8 g

Actual yield of CaCO₃ = 22.6 g

Theoretical yield = ?

Percent yield = ?

Limiting reactant = ?

Solution:

Chemical equation:

CaO + CO₂   → CaCO₃

Number of moles of CaO:

Number of moles  = Mass /molar mass

Number of moles = 14.4 g / 56.1 g/mol

Number of moles  = 0.26 mol

Number of moles of CO₂:

Number of moles = Mass /molar mass

Number of moles = 13.8 g / 44 g/mol

Number of moles = 0.31 mol

Now we will compare the moles of CO₂ and CaO with CaCO₃ .

                  CO₂         :                CaCO₃  

                  1               :                 1

                 0.31           :              0.31

                CaO           :               CaCO₃  

                 1                :                 1

                 0.26         :              0.26

The number of moles of  CaCO₃ produced by CaO are less it will be limiting reactant.

Mass of CaCO₃: Theoretical yield

Mass of CaCO₃ = moles × molar mass

Mass of CaCO₃ =0.26 mol × 100.1 g/mol

Mass of CaCO₃ =  26.03 g

Percent yield:

Percent yield = actual yield / theoretical yield × 100

Percent yield = 22.6 g/ 26.03 g × 100

Percent yield = 0.87× 100

Percent yield = 87%

Limiting reactant:

The number of moles of  CaCO₃ produced by CaO are less it will be limiting reactant.

7 0
3 years ago
1. Which elements are known as d-block elements?
Usimov [2.4K]

The d-block elements are found in groups 3, 4, 5, 6, 7, 8, 9, 10, 11, and 12 of the periodic table.

So your answer is A) Transition metals

8 0
3 years ago
Read 2 more answers
Identify each of the following as either an element or Compound. Write (E) for Element and (C)
castortr0y [4]

Carbon = C

Water = C

Aluminum foil = E

Plastic = E

Tin = E

Silicon dioxide = C

Helium = C

Arsenic = C

Carbon dioxide = C

Sodium Chloride = C

4 0
3 years ago
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