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Angelina_Jolie [31]
3 years ago
9

(25points) Explain in your own words the difference between atomic mass and atomic number. Where can you find this information o

n the periodic table?
Chemistry
2 answers:
Fiesta28 [93]3 years ago
8 0

Answer:

No time for it Ill help soon qw q

Explanation: And yes you know that 2332423 .

Eduardwww [97]3 years ago
6 0

Answer:

Atomic mass= The number of protons and neutrons in the atom

Atomic Number= Just the number of protons

Explanation:

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How many moles are in 2.54 * 10^73 atoms of copper?
Anton [14]

Answer:

= 3.99 ⋅ m o l ⋅ copper atoms  ...a mass of approx.  250 ⋅ g

Explanation:

5 0
3 years ago
Someone please help me real quick pls :(
Genrish500 [490]
Anti-acids because they contain Alkaline ion that chemically neutralizes stomach acid
8 0
3 years ago
When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced.
sp2606 [1]

Answer:

Mass of CaCl₂ =  20 g

CaCO is presewnt in excess.

Mass of of CaCO₃ remain unreacted =  7.007 g

Explanation:

Given data:

Mass of calcium carbonate = 25 g

Mass of hydrochloric acid = 13.0 g

Mass of calcium chloride produced = ?

Chemical equation:

CaCO₃ + 2HCl  →  CaCl₂  + H₂O + CO₂

Number of moles of CaCO₃:

Number of moles of CaCO₃ = Mass /molar mass

Number of moles of CaCO₃= 25.0 g / 100.1 g/mol

Number of moles of CaCO₃ = 0.25 mol

Number of moles of HCl:

Number of moles of  HCl = Mass /molar mass

Number of moles of HCl = 13.0 g / 36.5 g/mol

Number of moles of HCl = 0.36 mol

Now we will compare the moles of CaCl₂ with HCl and CaCO₃ .

                  CaCO₃         :               CaCl₂

                    1                 :               1

                 0.25              :            0.25

                HCl                :                CaCl₂

                 2                   :                    1

                 0.36            :                  1/2 × 0.36 = 0.18 mol

The number of moles of CaCl₂ produced by HCl are less it will be limiting reactant.

Mass of CaCl₂ = moles × molar mass

Mass of CaCl₂ =0.18 mol × 110.98 g/mol

Mass of CaCl₂ =  20 g

The calcium carbonate is present in excess.

                HCl                :                CaCO₃

                 2                   :                    1

                 0.36            :                  1/2 × 0.36 = 0.18 mol

So, 0.18 moles react with 0.36 moles of HCl.

The moles of CaCO₃ remain unreacted = 0.25 -0.18

The moles of CaCO₃ remain unreacted = 0.07 mol

Mass of of CaCO₃ remain unreacted = Moles × molar mass

Mass of of CaCO₃ remain unreacted = 0.07 mol × 100.1 g/mol

Mass of of CaCO₃ remain unreacted =  7.007 g

7 0
3 years ago
How many moles of solute are in 53.1 mL of 12.5M HCI?
Deffense [45]
Molarity = moles of solute/volume of solution in liters.

From this relation, we can figure out the number of moles of solute by multiplying the molarity of the solution by the volume in liters.

We have 53.1 mL, or 0.0531 L, of a 12.5 M, or 12.5 mol/L, solution. Multiplying 12.5 mol/L by 0.0531 L, we obtain 0.664 moles. So, in this volume of solution, there are 0.664 moles of solute (HCl).
6 0
3 years ago
If the vapor pressure of ethanol at 34.7degree C is 100
saw5 [17]

Answer:

we will use the Clausius-Clapeyron equation to estimate the vapour pressures of the boiling ethanol at sea level pressure of 760mmHg:

 ln (P2/P1) = \frac{ΔvapH}{R}([tex]\frac{1}{T1}-\frac{1}{T2})

where

P1 and P2 are the vapour pressures at temperatures  T1 and T2

Δ vapH  = the enthalpy of vaporization of the ETHANOL

R  = the Universal Gas Constant

In this problem,

P 1 = 100 mmHg

;  T 1 = 34.7 °C = 307.07 K

P 2 = 760mmHg

T 2 =T⁻²=?

Δ vap H = 38.6 kJ/mol

R = 0.008314 kJ⋅K -1 mol -1

ln ( 760/10)=(0.00325 - T⁻²) (38.6kJ⋅mol-1 /0.008314 )

0.0004368=(0.00325 - T⁻²)  

T⁻²=0.002813

T² = 355.47K

6 0
3 years ago
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