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notsponge [240]
3 years ago
13

Which factor is a component of skill-related fitness?

Physics
2 answers:
lukranit [14]3 years ago
6 0
There are six skill-related fitness components: agility, balance, coordination<span>, </span>speed<span>, power, and reaction time. Skilled athletes typically excel in all six areas. Agility is the ability to change and control the direction and position of the body while maintaining a constant, rapid motion.</span>
torisob [31]3 years ago
4 0

Answer: Balance

Explanation:  

The six components of skill-related fitness are Agility, Balance, Speed, Power, Coordination and Reaction time

Agility is a skill that would help the athletes to dodge their opponents in an efficient manner  

Balance is a skill that would help to prevent sportsmen from falling over

Speed is a skill that would help the sportsmen to move into position quickly

Power is a skill that would help to put more input while playing e.g. jumping higher etc

Coordination is a skill that would help to move quickly and smoothly during physical activity

Reaction time is a skill that would help to make a fast start, and respond quicker

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WILL GIVE BRAINLY!!!
Gnoma [55]
The answer is apogee my dude
7 0
3 years ago
A bus travelled 160 km in 4 hours, another bus travelled 175 km in 5 hours, which bus moved faster? ​
Arisa [49]

Answer:

Answer:

Bus travels 160 km in 4 hours

Speed of bus = 160/4 = 40 km/hr

Train travels 320 km in 5 hours

Speed of train = 320/5 = 64 km/hr

In one hour, bus travels 40 km and train travels 64 km.

Ratio = 40:64 = 5:8

6 0
3 years ago
Read 2 more answers
Pls help mee
NISA [10]

Answer:

the Arrow X shows the direction of amplitude

Explanation:

As the amplitude is the maximum displacement of a wave from the mean position

8 0
2 years ago
The temperature of a small metal cube is 75°c. A student places the cube into an insulated container of water at a temperature o
eduard
We can't tell without more information. We know it will be higher than 40 and lower than 75, but we don't know exactly where it will settle. In order to work that out, we would need to know the volumes of the water and the cube, and WHAT metal the cube is made of.
7 0
3 years ago
A bimetallic strip (brass/steel), which is straight at room temperature, will be immersed in boiling water and allowed to equili
lakkis [162]

The thermal expansion of the materials allows to find the deflection of the bimetallist strip is Δy = 3.48 cm

given paramers

    * Bimetallic brass / steel tape

    * Initial temperature, room temperature T = 20ºC

    * Final temperature, boiling water  = 100ºC

    * initial length L₀ = 222mm (1cm / 10mm) = 22.2cm

    * thickness of bimetallic tape e = 0.036 inch (2.54 cm/1 inch) = 0.0914 cm

to find

    * perpendicular deviation or deflection (Δy)

Thermal expansion is the phenomenon of change in the length of a body due to the change in temperature, due to the increase in the length of the atomic and molecular bonds, macroscopically it is described by

        ΔL = α L₀ ΔT

ΔL and ΔT are the variation of the length and temperature respectively, L₀ is the initial length and α the coefficient of expansion ends.

In this case we have a strip formed by two materials with different coefficient of thermal expansion,

Brass       α_{brass}   = 19 10⁻⁶ ºC⁻¹

Steel       α_{steel}    = 11 10⁻⁶ ºC⁻¹

In the attached we can see a diagram of the process, as the temperature increases, the material with greater thermal expansion lengthens more, so the system must curve towards the center of the material with less

thermal expansion. Let's find the length of the strip for each material

brass          L_{f brass} - L₀ = α_{brass} L₀ ΔT

Steel           L_{f steel} - L₀ = \alpha_{steel} L₀ ΔT

Note that the initial length is the same for the two materials and that the strip is in thermal equilibrium at room temperature.

If we assume that we have an arc of circumference, we can write the length of the arc

        θ = L / r

where θ is the angle in radines, L the length of the arc and r the radius of curvature, let's write this equation for each material

brass     L_{f \ brass} =θ r₁

steel      L_{f \ steel} = θ r₂

we substitute in our equations

           θ r₁ - L₀ = α_{brass} L₀ ΔT

           θ r₂ - L₀ = α_{steel} L₀ ΔT

let's subtract the two equations

           θ (r₁- r₂) = L₀ ΔT (α_{brass} - α_{steel})

the thickness of the strip is

           e = r₁ -r₂

           θ = Lo \ \Delta T \ \frac{\alpha_{brass} - \alpha_{steel}}{e}

we calculate

           θ = 22.2 \ (100-20) \ \frac{(19-11) \ 10^{-6}}{0.0914}

           θ = 0.155 rad

Let's use trigonometry to find the perpendicular deflection

          tan θ = Δy / L₀

          Δy = L₀ tan θ

          Δy = 22.2 tan 0.155

          Δy = 3.48 cm

Using the thematic expansion of the two materials we find the deflection of the bimetallist strip is 3.38 cm

Learn more about thermal expansion here: brainly.com/question/18717902

7 0
3 years ago
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