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Sergeu [11.5K]
2 years ago
8

1. A bicycle initially moving with a velocity

Physics
1 answer:
ki77a [65]2 years ago
7 0

Answer:

\boxed {\boxed {\sf 15 \ m/s \ or \ 15 \ m*s^{-1}}}

Explanation:

We are asked to find the final velocity. We are given the acceleration, time, and initial velocity, so we can use the following kinematics formula.

v_f= v_i+ at

In this formula, v_f is the final velocity, v_i is the initial velocity, a is the acceleration, and t is the time.

The bicycle has an initial velocity of 5.0 m *s⁻¹ or m/s, acceleration of 2 m/s², and a time of 5 seconds.

\bullet \  v_i = 5.0 \ m/s \\\bullet \  a= 2\ m/s^2\\\bullet \  t= 5  \ s

Substitute the values into the formula.

v_f=5.0 \ m/s + ( 2\ m/s^2 * 5 \ s)

Solve inside the parentheses.

  • \frac {2 \ m}{s^2}* 5 \ s = \frac{ 2 \ m}{s} * 5 = \frac{ 10 \ m}{s} = 10 \ m/s

v_f= 5.0 \ m/s + (10 \ m/s)

Add.

v_f= 15 \ m/s

The units can also be written as:

v_f= 15 \ m*s^{-1}

The bicycle's final velocity is 15 meters per second.

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A metal rod has a moves with a constant velocity of 40 cm/s along two parallel metal rails through a magnetic field of 0.575 T.
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Answer:

2.12/R mW

Explanation:

The electrical power, P generated by the rod is

P = B²L²v²/R where B = magnetic field = 0.575 T, L = length of metal rod = separation of metal rails = 20 cm = 0.2 m, v = velocity of metal rod = 40 cm/s = 0.4 m/s and R = resistance of rod = ?

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=  B²L²v²/R

So, P = (0.575 T)² × (0.2 m)² × (0.4 m/s)²

= 0.002116/R W

= 2.12/R mW

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