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3 years ago

Which statement best describes how reproduction leads to natural selection in a population?

Physics

2 answers:

lorasvet [3.4K]3 years ago

8 0

Organisms overproduce offspring, so only some survive and pass on their traits.

Natural selection is the fitting of a population to its environment.

Explanation:

Most organisms produce more than two or more offspring in their lifetime. Therefore the subsequent generations ideally have more individuals than the previous. However, naturally, the population size does not grow indefinitely. This is because some individuals do not survive to pass their genes to the next generation. Natural selection chooses the best fit individuals to habitat, and these live long enough to pass their traits to the next generation. Natural selection powers the evolution of a population even as environment changes

Learn More:

For more on natural selection check out;

brainly.com/question/12495043

brainly.com/question/1184863

#LearnWithBrainly

umka2103 [35]3 years ago

8 0

Answer:

The correct answer is C or Organisms overproduce offspring, so only some survive and pass on their traits.

Explanation:

I got 100% on this test.

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3 years ago

A plane is landing. It started at 400m/s and ended up at 50m/s after 30 seconds. What is it's acceleration?

quester [9]

Give u = start velocity

v = end velocity

v = u + at

50 = 400 + a*30

30a = -350

a = -116.67 m/ $s^{2}$

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Vector Quantity must have direction.

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3 years ago

A billiard ball is moving in the x-direction at 30.0 cm/s and strikes another billiard ball moving in the y-direction at 40.0 cm

PSYCHO15rus [73]

Explanation:

Given that,

Initial speed of the billiard ball 1, u = 30i cm/s

Initial speed of another billiard ball 2, u' = 40j cm/s

After the collision,

Final speed of first ball, v = 50 cm/s

Final speed of second ball, v' = 0 (as it stops)

Let us consider that both balls have same mass i.e. m

Initial kinetic energy of the system is :

$K_i=\dfrac{1}{2}mu^2+\dfrac{1}{2}mu'^2\\\\K_i=\dfrac{1}{2}m(u^2+u'^2)\\\\K_i=\dfrac{1}{2}m((30)^2+(40)^2)\\\\K_i=1250m\ J$

Final kinetic energy of the system is :

$K_f=\dfrac{1}{2}mv^2+\dfrac{1}{2}mv'^2\\\\K_f=\dfrac{1}{2}m(v^2+v'^2)\\\\K_f=\dfrac{1}{2}m((50)^2+(0)^2)\\\\K_f=1250m\ J$

The change in kinetic energy of the system is equal to the difference of final and initial kinetic energy as :

$\Delta K=K_f-K_i\\\\\Delta K=1250m-1250m\\\\\Delta K=0$

So, the change in kinetic energy of the system as a result of the collision is equal to 0.

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4 years ago

On a windless day, two identical balls P and Q are dropped from the top and the middle of a tower at exactly the same time as sh

Kruka [31]

Answer: time is the same

Explanation: the distance(H) is the same in each case .

we drop the balls , no drag force using basic kimnematics

y =gt*t/2 , yo=0 , vo=0 , y=H , so : t= sqrt(2H/g)

comment: if distance H starts to grow....we could begin to note a difference because of gravity g is smaller as we go up

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3 years ago

Which type of graph is best for analyzing quantitative dependent and independent variables?

tensa zangetsu [6.8K]

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3 years ago