$\begin{gathered} F=qvBsinθ \\ where\text{ F is the magnetic force} \\ q\text{ is the charge} \\ v\text{ is the velocity of the charge} \\ Bis\text{ the magnetic field} \\ \theta\text{ is the angle} \end{gathered}$

Step 1

Let

$\begin{gathered} q=1.25*10^{-4\text{ }}C \\ v=5200\frac{m}{s} \\ \theta=37\text{ \degree} \\ B=8.49*10^{-4}T \end{gathered}$

now, replace

$\begin{gathered} F=qvBs\imaginaryI n\theta \\ F=1.25*10^{-4}\text{ C*5200 }\frac{m}{s}*8.49*10^{-4}Tsin(37) \\ F=0.0003321\text{ Newtons} \\ \end{gathered}$

so, the answer is

0.0003321 Newtons

I hope this helps you

7 0

1 year ago

Can an object be in mechanical equilibrium when only a single force acts on it? explain.

elena-s [515]

No because if there is a force, there is acceleration which means the object is getting faster.

3 0

3 years ago

The speed of light in ________ is about 230 million m/s.

Vladimir [108]

Answer:

Water

Explanation:

The speed of light in water is about 230 million m/s.

8 0

3 years ago

A ball is dropped from the rest from a high window of a tall building and called for 4 seconds. Neglecting air resistance, the f

diamong [38]

Answer:

-39.2m/s

Explanation:

Given that :

t = 4secs

g = -9.8m/s^2

v = ?

u = 0m/s ( since it was at rest )

V = u +at............. 1

Where v is the final velocity

a = -g = -9.8m/s^2 since the ball was dropped from a height which will eventually make it move against gravity

t = 4secs

Substitute the values into 1

v = 0 - 9.8×4

v = -39.2m/s

3 0

3 years ago