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Vadim26 [7]
3 years ago
6

I need help with this. Lab: Conservation of Linear MomentumAssignment: Lab Report Urgent!!

Physics
2 answers:
kifflom [539]3 years ago
8 0
It won’t let me view it
Romashka-Z-Leto [24]3 years ago
4 0
It won’t let us view your image below
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A meter stick whose mass is 330 grams lies on ice. You pull at one end of the meter stick, at right angles to the stick, with a
Sophie [7]

Answer:

initial magnitude will be 9 N and direction will be to the right

Explanation:

force= 9N

mass m= 330 grams

acceleartion = a

from newtons 2nd law of motion we write

F= \frac{\mathrm{dP} }{\mathrm{d} t}

dP is the chage in momentum dt is time taken and F is the Force applied

9N= \frac{\mathrm{dP} }{\mathrm{d} t}

this shows that the rate of change of momentum is 9 N

we also know that F= ma

putting values we get

9= 0.330\times a

a= 27.27 m/sec^2

The direction of acceleration will along the direction of force applied. So will be the direction of change momentum as in F=ma,  mass is the scalar quantity and direction of force dictates the direction of motion. Hence, initial magnitude will be 9N and direction will be to the right

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3 years ago
Four 5-gram blocks of metal are sitting out in the sun and absorb the same amount of heat energy. Use the following specific hea
julsineya [31]

Answer:

There is NO DATA??

Explanation:

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3 years ago
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Which symbol and unit of measurement are used for electric current?
Burka [1]

Answer: Symbol is I and unit A

Explanation: A represents Amperes

HOPE THIS HELPS!!!!!!!!

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The most abundant climate type over the face of the earth is
erastovalidia [21]
It is Humid Continental but i could be wrong
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3 years ago
7. How much thermal energy is absorbed when 10.0 g of ice at 0.0 degrees C changes phase to liquid water at 0.0 degrees C? The m
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Answer:

3.34 kJ

Explanation:

FIrst of all, we need to calculate the number of moles corresponding to 10.0g of ice. This is given by

n=\frac{m }{M_m}

where

M_m = 18.02 g/mol is the molar mas

m = 10.0 g is the mass

Substituting

n=\frac{m}{M_m}=\frac{10 g}{18.02 g/mol}=0.555 mol

Now we know that the heat of fusion is

H_{fus}=6.01 kJ/mol

so the thermal energy needed to fuse the ice is

Q=n H_{fus} = (0.555 mol)(6.01 kJ/mol)=3.34 kJ

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