Answer:
34 is it
Step-by-step explanation:
Answer:
Option D. 8 units
Step-by-step explanation:
step 1
Find the area of rectangle
The area of rectangle is
step 2
Find the length side of the square with the same area of rectangle
The area of a square is
where
b is the length side of the square
we have
substitute
take the square root both sides
therefore
The length side of the square is 8 units
Answer:
Explanation:
3 + 2x - y = 0
Or 2x - y = -3 (1)
-3-7y = 10x
Or -10x - 7y = 3 (2)
2x - y = -3 (1)
-10x - 7y = 3 (2)
———————
Multiply 5 to (1)
5(2x - y = -3)
-10x - 7y = 3
———————
10x - 5y = -15
-10x - 7y = 3
———————
-12y = -12
y = -12/-12
y = 1
Plug y value in (1)
2x - 1 = -3
2x = -3 + 1
2x = -2
x = -2/2 = -1
Therefore, x = -1 and y = 1
Answer:
the answers is -4
Step-by-step explanation:
-1+3 I think this the answer
Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
