I think the correct answer would be none, because the wall will block the radiation. Alpha particles can only penetrate a very thin sheet of paper and is totally blocked by the concrete. As these particles move through the air, it loses energy from the collisions with air molecules making it less penetrating.<span />
Answer:
22.81 g
Explanation:
Given that:
Pressure = 1.68 atm
Temperature = 46 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (46 + 273.15) K = 319.15 K
Volume = 8.99 L
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
1.68 atm × 8.99 L = n × 0.0821 L.atm/K.mol × 319.15 K
<u>⇒n = 0.5764 moles
</u>
Given that :
Amount of methane = 4.88 g
Molar mass = 16.04 g/mol
The formula for the calculation of moles is shown below:
Thus,

<u>Moles of Krypton = Total moles - Moles of methane = 0.5764 - 0.3042 moles = 0.2722 moles</u>
Also, Molar mass of krypton = 83.798 g/mol
So,
The formula for the calculation of moles is shown below:
Thus,
<u>Mass of krypton = 22.81 g</u>
Answer:
Because it uses the residual energy of the fluid used by the first engine.
Explanation:
A combined cycle power generation counts with two heat engines that work in tandem from the same source of heat. The engines turn the energy into mechanical energy.
The cycle is much more efficient than the other, almost 60% more.
I hope this answer helps you.
Answer:
1. ![R=k[A]^1[B]^2](https://tex.z-dn.net/?f=R%3Dk%5BA%5D%5E1%5BB%5D%5E2)
2. ![R=k[B]^1](https://tex.z-dn.net/?f=R%3Dk%5BB%5D%5E1)
3. ![R=k[A]^0[B]^0=k](https://tex.z-dn.net/?f=R%3Dk%5BA%5D%5E0%5BB%5D%5E0%3Dk)
4. ![R=k[A]^1[B]^{-1}](https://tex.z-dn.net/?f=R%3Dk%5BA%5D%5E1%5BB%5D%5E%7B-1%7D)
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
(1) is second order in B and overall third order.
2A + B → C
Order of the reaction = sum of stoichiometric coefficient
= x + 2 = 3
x = 1
Rate of the reaction =R
![R=k[A]^1[B]^2](https://tex.z-dn.net/?f=R%3Dk%5BA%5D%5E1%5BB%5D%5E2)
(2) is zero order in A and first order in B.
2A + B → C
Rate of the reaction =R
![R=k[A]^0[B]^1=k[B]^1](https://tex.z-dn.net/?f=R%3Dk%5BA%5D%5E0%5BB%5D%5E1%3Dk%5BB%5D%5E1)
Order of the reaction = sum of stoichiometric coefficient
= 0 + 1 = 1
(3) is zero order in both A and B .
2A + B → C
Order of the reaction = sum of stoichiometric coefficient
= 0 + 0 = 0
Rate of the reaction =R
![R=k[A]^0[B]^0=k](https://tex.z-dn.net/?f=R%3Dk%5BA%5D%5E0%5BB%5D%5E0%3Dk)
(4) is first order in A and overall zero order.
2A + B → C
Order of the reaction = sum of stoichiometric coefficient
= 1 + x = 0
x = -1
Rate of the reaction = R
![R=k[A]^1[B]^{-1}](https://tex.z-dn.net/?f=R%3Dk%5BA%5D%5E1%5BB%5D%5E%7B-1%7D)