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3 years ago

Luke scored 21 goals in 7 soccer games.if he scores goals at the same rate,how many goals will he score in 23 games?

Mathematics

2 answers:

Vesna [10]3 years ago

8 0

49 is the answer because 7x7 is 49

sashaice [31]3 years ago

3 0

21 divided by 7 is 3. 3 times 23 is 69. Luke will score 69 goals in 23 games

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A 12-member jury is to be selected from 15 men and 13 women. Find the probability that this jury has 6 or 7 males.

Bas_tet [7]

Answer:

The right solution is "0.5545".

Step-by-step explanation:

According to the question,

The probability of having 6 or 7 males will be:

= $P(6 \ males)+ P(7 \ males)$

= $\frac{15_C_6\times 13_C_6}{28_C_{12}} + \frac{15_C_7\times 13_C_5}{28_C_{12}}$

= $\frac{5005\times 1716+6435\times 1287}{30421755}$

= $\frac{16870425}{30421755}$

= $0.5545$

8 0

3 years ago

PLEASE I NEED HELP QUICK:

nignag [31]

1/3 is 0.3333333 and you round it by the 3rd three, so it looks like 0.334

3 0

3 years ago

How to write parallel and perpindicular lines

koban [17]

Answer:

Parallel lines are straight lines that don't ever touch. Think of a railroad track.

Perpendicular lines are lines that meet and make a 90 degree angle

7 0

3 years ago

Find the solutions to the system of equations. Select all that apply. Y=x^2-1 y=2x-2

Sliva [168]

Answer:

Option C (1, 0)

Step-by-step explanation:

We have a system with the following equations:

$y = x ^ 2-1\\\\y = 2x-2$

The first equation is a parabola.

The second equation is a straight line

To solve the system, substitute the second equation in the first and solve for x.

$2x-2 = x ^ 2 -1$

Simplify

$x ^ 2-2x + 1 = 0$

You must search for two numbers that when you add them, obtain as a result -2 and multiplying both results in 1.

These numbers are -1 and -1

Therefore

$x ^ 2-2x + 1= (x-1)(x-1)\\\\x ^ 2-2x + 1= (x-1)^2=0$

Finally the solutions are

$x = 1\\y =0$

8 0

3 years ago

Read 2 more answers

Solve the equation on the interval [0,2π). cos^4x=cos^4xcscx

Alisiya [41]

$\bf cos^4(x)=cos^4(x)csc(x)\\\\
-----------------------------\\\\
cos^4(x)=cos^4(x)\cfrac{1}{sin(x)}\implies cos^4(x)=\cfrac{cos^4(x)}{sin(x)}
\\\\\\
cos^4(x)sin(x)=cos^4(x)\implies cos^4(x)sin(x)-cos^4(x)=0
\\\\\\
cos^4(x)[sin(x)-1]=0\to 
\begin{cases}
cos^4(x)=0\to x=cos^{-1}(0)\\
----------\\
sin(x)-1=0\\
sin(x)=1\to x=sin^{-1}(1)
\end{cases}$

$\bf \measuredangle x = cos^{-1}(0)\implies \measuredangle x = 
\begin{cases}
\frac{\pi }{2}\\\\
\frac{3\pi }{2}
\end{cases}
\\\\\\
\measuredangle x=sin^{-1}(1)\implies \measuredangle x=\frac{\pi }{2}$

3 0

3 years ago