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Greeley [361]
3 years ago
5

How much space does 1kg of air occupy? The density of the air is 0.0013g/mL

Physics
1 answer:
nexus9112 [7]3 years ago
3 0
The basic relationship between mass m, volume V and density d is given by
d= \frac{m}{V}
re-arranging the equations and using m=1 kg and d=0.0013 g/mL = 0.0013 kg/L, we find the volume:
V= \frac{m}{d}= \frac{1 kg}{0.0013 kg/L}=769.2 L
and since 1 L = 1 m^3, this corresponds to 769.2 m^3 of air.
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Answer:

\theta = 106.3 degree

Explanation:

As we know that

\vec w = -\hat i + 7\hat j

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also we know that

\vec v. \vec w = -14

it is given as

\vec v. \vec w = (-\hat i + 7\hat j).(7\hat i - \hat j)

\vec v. \vec w = - 7 - 7 = -14

also we can find the magnitude of two vectors as

|v| = \sqrt{(-1)^2 + (7)^2}

|v| = \sqrt{50}

similarly we have

|w| = \sqrt{(7^2) + (-1)^2}

|w| = \sqrt{50}

now we know the formula of dot product as

\vec v. \vec w = |v||w| cos\theta

-14 = (\sqrt{50})^2cos\theta

\theta = cos^{-1}(\frac{-14}{50})

\theta = 106.3 degree

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3 years ago
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