3 years ago

Choose the equation of the line.y=-3x - 13y=-3x - 5y=-3x +5y=-1/3x+13

Physics

2 answers:

Nookie1986 [14]3 years ago

4 0

Answer: it’s B -3x-5

Explanation: just answered it and got it correct.

professor190 [17]3 years ago

4 0

Answer:

Explanation:

Just got it correct

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Part b)

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As per momentum conservation we know that there is no external force on this system so initial and final momentum must be same

So we will have

$m_1v_1 + m_2v_2 + m_3v_3 = 0$

$(5 \times 10^{-27})(6 \times 10^6\hat j) + (8.4 \times 10^{-27})(4 \times 10^6\hat i) + (3.6 \times 10^{-27}) v = 0$

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Part b)

By equation of kinetic energy we have

$E = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2 + \frac{1}{2}m_3v_3^2$

$E = \frac{1}{2}(5 \times 10^{-27})(6\times 10^6)^2 + \frac{1}{2}(8.4 \times 10^{-27})(4 \times 10^6)^2 + \frac{1}{2}(3.6 \times 10^{-27})(8.33^2 + 9.33^2) \times 10^{12}$

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2 years ago

Choose the equation of the line.y=-3x - 13y=-3x - 5y=-3x +5y=-1/3x+13​

Choose the equation of the line.y=-3x - 13y=-3x - 5y=-3x +5y=-1/3x+13